Geometry (Part-3)

Total Questions: 50

1. In ∆ABC BD is perpendicular to AC. E is a point on BC such that ∠BEA = xº. If ∠EAC = 38º and ∠EBD = 40º then the value of x is: [SSC CHSL 03/07/2019 (Morning)]

1. (a) 88º
2. (b) 68º
3. (c) 78º
4. (d) 72º

Correct Answer: (a) 88º

Solution:

2. A circle is inscribed in a quadrilateral ABCD, touching sides AB, BC, CD and DA at P, Q, R, and S respectively. If AS = 8cm , BC = 11cm and CR = 5cm then the length AB (in cm) is equal to: [SSC CHSL 02/07/2019 (Evening)]

1. (a) 12
2. (b) 13
3. (c) 16
4. (d) 14

Correct Answer: (d) 14

Solution:

3. In ∆ABC , ∠A = 90º. If BL and CM are medians, then: [SSC CHSL 02/07/2019 (Evening)]

1. (a)
2. (b)
3. (c)
4. (d)

Correct Answer: (b)

Solution:

4. Two concentric circles are of radius 15 cm and 9 cm. What is the length of the chord of the larger circle which is tangent to the smaller circle (in cm)? [SSC CHSL 02/07/2019 (Morning)]

1. (a) 24
2. (b) 18
3. (c) 20
4. (d) 25

Correct Answer: (a) 24

Solution:

5. Tangents AB and AC are drawn to a circle from a point A, such that, ∠BAC = 40°. A chord CP is drawn parallel to BA. The measure of ∠CBP is: [SSC CHSL 01/07/2019 (Evening)]

1. (a) 55°
2. (b) 45°
3. (c) 35°
4. (d) 40°

Correct Answer: (d) 40°

Solution:

6. In a circle with centre O, AD is a diameter and AC is a chord. B is a point on AC, such that OB = 5 cm and ∠OBA = 60°. If ∠DOC = 60º then what is the length of BC (in cm) ? [SSC CHSL 01/07/2019 (Evening)]

1. (a) 4
2. (b) 3√5
3. (c) 5√3
4. (d) 5

Correct Answer: (d) 5

Solution:

7. Chords AB and CD of a circle, when produced, meet at point P outside the circle. If AB = 6 cm, CD = 3 cm and PD = 5 cm, then PB is equal to: [SSC CGL 11/06/2019 (Morning)]

1. (a) 6 cm
2. (b) 6.25 cm
3. (c) 5 cm
4. (d) 4 cm

Correct Answer: (d) 4 cm

Solution:

8. In a ∆ ABC, the sides are AB = 16cm, AC = 63cm BC = 65cm. From A, a straight line AM is drawn up to the midpoint M of side BC. Then the length of AM is equal to in (cm): [SSC CGL 10/06/2019 (Evening)]

1. (a) 32.5
2. (b) 24.5
3. (c) 23.5
4. (d) 31.5

Correct Answer: (a) 32.5

Solution:

9. In a ∆ ABC, AD is the median and G is a point on AD such that AG : GD = 2 :1 , then ar(∆ BDG) : (△ ABC) is equal to: [SSC CGL 10/06/2019 (Afternoon)]

1. (a) 1:4
2. (b) 1:9
3. (c) 1:6
4. (d) 1:3

Correct Answer: (c) 1:6

Solution:

10. From a point P, outside a circle, PAB is a secant and PT is a tangent to the circle, where A, B and T are points on the circle. If PT = 5 cm, PA = 4 cm and AB = x , then x is equal to : [SSC CGL 10/06/2019 (Afternoon)]

1. (a) 2.25
2. (b) 2.75
3. (c) 2.45
4. (d) 1.75

Correct Answer: (a) 2.25

Solution:

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