Solution:Given, external dimensions of the
box are length 12 cm, breadth 10
cm and height 8 cm and inner surface
area is 376 cm².Let the thickness of the wood be x cm.
Then internal dimensions of the box are
Length (l) = (12 - 2x) cm
Breadth (b) = (10 - 2x) cm
Height (h) = (8 - 2x) cm
We know that,
Inner surface area = 2(lb + bh + hI)
376 = 2[ (12 - 2x) (10 - 2x) + (10 - 2x) (8 - 2x)]
+ (8 - 2x) (12 - 2x)]
⇒ 188 = [120 - 44x + 4x² + 80
- 36x + 4x² + 96 - 40x + 4x²]
⇒ 47 = 74 - 30x + 3x²
⇒ x² - 10x + 9 = 0
⇒ (x - 1)(x - 9) = 0
⇒ x = 1 and x = 9 (not possible)
Hence, the thickness of wood is 1 cm.