Series – Railway Reasoning part – 2

Total Questions: 50

1. 5, 13, 23, 49, ?, 193 [Group - D 18/08/2022 ( Morning )]

Correct Answer: (b) 95
Solution:

2. 2, 14, 70, 210, ? [Group - D 18/08/2022 ( Afternoon)]

Correct Answer: (d) 210
Solution:

3. 4, 5, 12, 39, 160, ? [Group - D 18/08/2022 ( Evening)]

Correct Answer: (a) 805
Solution:

4. Select the option that represents the letters that, when placed from left to right in the same sequence in the blanks below, will complete the letter series. [Group - D 18/08/2022 ( Evening)]

B _ XT _ _ HY _ MB _ Z _ M

Correct Answer: (c) HMBHTT

5. 7, 20, 37, 56, 79, 108, ? [Group - D 22/08/2022 ( Morning)]

Correct Answer: (d) 139
Solution:

Each term is increasing by a consecutive prime number.

6. 28, 29, 31, 35, 43, ? [Group - D 22/08/2022 ( Afternoon)]

Correct Answer: (d) 59
Solution:

7. EHT-13, HKW-17, LOA-22, QTF-28, WZL-35, ? [Group - D 22/08/2022 ( Afternoon)]

Correct Answer: (d) DGS - 43
Solution:

First letter ⇒ E + 3 = H,
H + 4 = L, L + 5 = Q, Q + 6 = W, W + 7 = D
second letter ⇒ H + 3 = K, K + 4 = O,
O + 5 = T, T + 6 = Z, Z + 7 = G
third letter ⇒ T + 3 = W, W + 4 = A,
A + 5 = F, F + 6 = L, F + 7 = S
number ⇒ 13 + 4 = 17, 17 + 5 = 22,
22 + 6 = 28, 28 + 7 = 35, 35 + 8 = 43
Hence required pair = DGS - 43

8. ACE 9, BDF 12, GIK 27, HJL 30, ?, NPR 48, SUW 63 [Group - D 22/08/2022 ( Evening)]

Correct Answer: (b) MOQ 45
Solution:

Given series: ACE 9, BDF 12,
GIK 27, HJL 30, ?, NPR 48, SUW 63
In all the above set of letters, there is a
difference of 2, as A + 2 = C, C + 2 = E
Similarly, B + 2 = D, D + 2 = F
G + 2 = I, I + 2 = K and so on
there is only one option (b) that satisfies
this condition i.e., M + 2 = O, O + 2 = Q
And for the number series 9, 12, 27, 30, ?
, 48, 63

9. 16, 18, 27, 55, 120,? [Group - D 22/08/2022 ( Evening)]

Correct Answer: (b) 246
Solution:

10. Select the option that represents the letters that, when placed from left to right in the same sequence in the blanks below, will complete the letter series. [Group - D 23/08/2022 ( Morning)]

C _ P R _ D T _ R N _ T _ R N _ T P _ N

Correct Answer: (a) TNPEPFR
Solution:

The series is as follows :
C T P R N / D T P R N / E T P R N / E T PRN
This series makes a pair of TNPEPFR