Light (Physics) (Part-2)Total Questions: 101. The amount of light entering into eye can be controlled and regulated by________. [S.S.C. Online Graduation Level (T-I) 4.06.2019 (Shift-III)](a) cornea(b) Pupil(c) Iris(d) retinaCorrect Answer: (c) IrisSolution:The amount of light entering into the eye can be controlled and regulated by the iris.2. Which of the following is NOT necessarily a part of a school laboratory compound microscope? [S.S.C. JE Mechanical Exam 22.03.2021 (Shift-I)](a) Mirror(b) Eye-piece(c) Objective lens(d) CameraCorrect Answer: (d) CameraSolution:Eye-piece, objective lens, and mirror are essential parts of the compound microscope of the school laboratory, while the camera is not a necessary part of it.3. Diopter is the SI of which of the following? [S.S.C. Online Stenographer 13.09.2017 (Shift-II)](a) wavelength(b) light intensity(c) power of the lens(d) Magnetic forceCorrect Answer: (c) power of the lensSolution:The SI unit of lens power is a diopter. The power of a convex lens is positive and that of a concave lens is negative. P=1/f (f in meters) where P = power of lens. f = focal length of the lens.4. What is the SI unit of lens power? [S.S.C. Online MTS (T-I) 5.08.2019 (Shift-II)](a) Watt(b) Kwh(c) Joule(d) dioptersCorrect Answer: (d) dioptersSolution:The SI unit of lens power is a diopter. The power of a convex lens is positive and that of a concave lens is negative. P=1/f (f in meters) where P = power of lens. f = focal length of the lens.5. The power of a lens is 2.0 D. Here 'D' stands for : [S.S.C. Online Graduation Level (T-I) 7.03.2020 (Shift-I)](a) Dioptre(b) Degree(c) Distance(d) DilationCorrect Answer: (a) DioptreSolution:The unit of power of a lens is expressed by diopter (D).6. Find the power of a convex lens, if the image is formed at a distance of 20 cm from the lens when the object is placed at a distance of 60 cm from the optical center on the other side of the lens? [S.S.C. Online CHSL (T-I) 31.01.2017 (Shift-III)](a) 3.33 diopters(b) 6.67 diopters(c) -6.67 diopters(d) -3.33 dioptersCorrect Answer: (b) 6.67 dioptersSolution:To find the power of a convex lens, we use the lens formula and the power formula. Let's solve this step by step. Given thatImage distance (v) = +20 cm (positive for a real image formed on the other side of the lens) Object distance (u) = -60 cm (negative as per the sign convention for the object distance) Focal length (f) needs to be calculated first, then power (P) will be derived. Step 1: Lens Formula The lens formula is: (1/f) = (1/v) - (1/u) (1/f) = (1/20) - (1/-60) Simplifying (1/f) = (1/20) + (1/60) = (4/60) = (1/15) So, the focal length f is: f=+15 cm (The positive sign indicates a convex lens.) Step 2: Power of the Lens The power P of a lens is given by: P=1/f (in meters) Convert the focal length from centimeters to meters: f = 15/100 = 0.15 m Now calculate the power: P = 1/0.15 = 10/1.5= 6.67 diopters (D)7. Find the power of a convex lens if the image formed is at a distance of 20 cm from the lens when the object is placed on the other side of the lens at 25cm from the optical centre? [S.S.C. Online CHSL (T-I) 31.01.2017 (Shift-I)](a) 1 diopters(b) -9 diopters(c) 9 diopters(d) -1 dioptersCorrect Answer: (c) 9 dioptersSolution:To find the power of a convex lens, we need to determine its focal length and then use the power formula. Let's solve this step-by-step using the lens formula.Given that : Object distance, u = −25 cm. Image distance, v = +20 cm. Lens formula: 1/f = (1/v) − (1/u) = (1/20) - (1/-25) = (1/20) + (1/25) = (5 + 4)/100 = 9/100 ∴ f = 100/9 cm Then P = 1/f (f in metres) = 1/100/(9 × 100) ⇒ 9 diopters 8. Find the power of a convex lens if the image formed is at a distance of 16 cm from the lens when the object is placed on the other side of the lens at 20 cm from the optical centre? [S.S.C. Online CHSL (T-I) 2.02.2017 (Shift-I)](a) 3.75 diopters(b)11.25 diopters(c) 3.75 diopters(d) 11.25 dioptersCorrect Answer: (d) 11.25 dioptersSolution:To find the power of a convex lens, we need to determine its focal length and then use the power formula. Let's solve this step-by-step using the lens formula.Given that : Object distance, u = −20 cm. Image distance, v = +16 cm. Lens formula: 1/f = (1/v) − (1/u) = (1/16) - (1/-20) = (1/16) + (1/20) = (5 + 4)/80 = 9/80 ∴ f = 80/9 cm Then P = 1/f (f in metres) = 1/80/(9 × 100) ⇒ (100 × 9)/80 ⇒ 11.25 diopters The power of the lens is positive.9. Find the power of a convex lens if the image formed is at a distance of 10 cm from the lens when the object is placed on the other side of the lens at 40cm from the optical centre? [S.S.C. Online CHSL (T-I) 30.01.2017 (Shift-I)](a) 12.5 diopters(b) 7.5 diopters(c)-12.5diopters(d)-7.5dioptersCorrect Answer: (a) 12.5 dioptersSolution:To find the power of a convex lens, we need to determine its focal length and then use the power formula. Let's solve this step-by-step using the lens formula.Given that : Object distance, u = −40 cm. Image distance, v = +10 cm. Lens formula: 1/f = (1/v) − (1/u) = (1/10) - (1/-40) = (1/10) + (1/40) = (4+1)/40 = 5/40 ⇒ 1/8 cm ∴ f = 40/5 cm ⇒ 8 cm Then P = 1/f (f in metres) = 1/8/100 ⇒ (100)/8 ⇒ 12.5 diopters The power of the lens is positive.10. Which of the following reflects more sunlight than the other three? [C.P.O. S.I. 5.06.2016 (Shift-I)](a) sand desert(b) land covered with fresh snow(c) plain land(d) paddy croplandCorrect Answer: (b) land covered with fresh snowSolution:The land covered with fresh snow reflects more sunlight than the other three given in the alternatives.Sand desert = 20-30% plain land = 25% Land covered by fresh snow = 85% Paddy cropland = 20-25%.Submit Quiz