BANK & INSURANCE (PERCENTAGE) PART 1Total Questions: 601. In a city, 55% of the population are males out of which only 80% are literate. If 85% of the population of the city is literate, then what percentage of the population are illiterate females?(a) 8% (b) 2.5% (c) 7.5%(d) 4%(e) 10%Correct Answer: (d) 4%Solution:Let total population = n Male population = 55% of n = 0.55n Illiterate male population = (100 - 80)% of 0.55n = 0.11n Illiterate population = (100 - 85)% of n = 0.15n Then, illiterate female population = 0.15n - 0.11n = 0.04n Therefore, percentage = (0.04n/n) x 100 = 4%2. Mahi spends 70% of her income every month and saves Rs.8400. If her income is increased by 25% while her expenditure is decreased by 25%, then her savings becomes -(a) Rs.20300 (b) Rs.17500 (c) Rs.18900 (d) Rs.21700 (e) Rs.23100Correct Answer: (a) Rs.20300 Solution:Initial monthly income = 8400 x 100/(100 - 70) = 28000 Initial monthly expenditure = 28000 - 8400 = 19600 New monthly income = (100 + 25)% of 28000 = 35000 New monthly expenditure = (100 - 25)% of 19600 = 14700 Therefore, new monthly savings = 35000 - 14700 = Rs.203003. Price of oil is decreased by 10% and the consumption of oil in a family is increased by 8%. By what percentage the expenditure of the family is changed?(a) 2.4% (b) 3.2% (c) 3.4%(d) 2.8% (e) 3.6%Correct Answer: (d) 2.8% Solution:Let initial price of oil = Rs. a per liter Initial oil consumption = b liters Initial expenditure = ab New price of oil = (100 - 10)% of a = 0.9a New oil consumption = (100 + 8)% of b = 1.08b New expenditure = 0.9a x 1.08b = 0.972ab Therefore, percentage decrease in expenditure = ((ab - 0.972ab)/ab) x 100 = 2.8%4. P initially had 240 kg almonds. He gave 30% of almonds to Q, 10% of almonds to R, 35% of almonds to S and rest to T. What is the difference between the quantity of almonds received by Q and T?(a) 18 kg (b) 6 kg (c) 24 kg (d) 30 kg(e) 12 kgCorrect Answer: (e) 12 kgSolution:Total quantity of almonds = 240 kg Quantity of almonds received by Q = 30% of 240 = 72 kgQuantity of almonds received by R = 10% of 240 = 24 kg Quantity of almonds received by S = 35% of 240 = 84 kg Quantity of almonds received by T = 240 - 72 - 24 - 84 = 60 kg Therefore, difference between the quantity of almonds received by Q and T = 72 - 60 = 12 kg5. Sum of two numbers A and C is 56 more than B. If A is 60% less than C and value of B is 28. B is approximately what percent more/less than A?(a) 9.33%(b) 16.67% (c) 11.25% (d) 18.99% (e) 6.45%Correct Answer: (b) 16.67% Solution:B = 28 A = 40% of C = 0.4C B + 56 = A + C (0.4C) + C = 28 + 56 C = 60, A = 0.4 x 60 = 24 Then, difference between A and B = 28 - 24 = 4 Therefore, percentage = (4/24) x 100 = 16.67% (approx.)6. In a business, A’s and B’s investments are respectively 125% and 75% of C’s investment and ratio of time periods of A, B and C is respectively 1 : 2 : 1. Find that A’s profit is what percent of B’s and C’s profit together?(a) 20% (b) 50%(c) 40%(d) 25% (e) 30%Correct Answer: (b) 50%Solution:So, A's investment = 125% of ‘4x’ = 5x And B's investment = 75% of ‘4x’ = 3x Ratio of profit shares of A, B and C respectively: (5x × 1): (3x × 2): (4x × 1) = 5:6: 4 Required percentage = [5/(6 + 4)] x 100 = 50%7. In a class of 400 students 40% are girls and rest are boys. 30% of the girls are honest and rest of the girls are dishonest. In case of boys 60% are dishonest and rest of the boys are honest. Find out what percentage of the students are honest?(a) 48% (b) 56%(c) 32%(d) 36% (e) 52%Correct Answer: (d) 36% Solution:Number of girls in the class = (0.4 x 400) = 160 Number of boys in the class = (400 - 160) = 240 Total number of honest girls = (0.3 x 160) = 48 Number of honest boys = (0.4 x 240) = 96 Total number of honest students = (96 + 48) = 144 Hence the required % = 144/400 x 100 = 36%8. In an exam, A got 28% marks and failed by 30 marks, B got 32% marks and failed by 20 marks. If C got 110 marks, then find his percentage?(a) 22% (b) 55%(c) 44% (d) 20% (e) 50%Correct Answer: (c) 44% Solution:Let maximum marks in the exam = ‘100x’ So, (28% of 100x) + 30 = (32% of 100x) + 20 28x + 30 = 32x + 20 x = 2.5 Maximum marks in the exam = 100 × 2.5 = 250 So, C's percentage in the exam = (110/250) × 100 = 44%9. Ratio of male to female employees in a company in 2002 is 5 : 6 and if next year male employees are increased by 20% while the female employees are decreased by 20%, then what is the ratio of male to female employees in the company in 2003?(a) 5 : 4 (b) 2 : 3 (c) 4 : 7 (d) 3 : 5 (e) None of theseCorrect Answer: (a) 5 : 4 Solution:Let number of male and female employees in the company in 2002 is 5x and 6x respectively. Male employees in 2003 = 120% of 5x = 6x Female employees in 2003 = 80% of 6x = 4.8x Required ratio = 6x : 4.8x = 5 : 410. Sum of twice of A and thrice of B is 130. When A is increased by 50% and B is decreased by 50%, then their sum becomes 45. What is the difference between A and B?(a) 10 (b) 14 (c) 15(d) 12 (e) 28Correct Answer: (a) 10 Solution:2A + 3B = 130 ⇒ A = (130 - 3B)/2 (100 + 50)% of A + (100 - 50)% of B = 45 A = 2x(45 - 0.5B)/3 Now, (130 - 3B)/2 = 2 × (45 - 0.5B)/3 390 - 9B = 180 - 2B 7B = 210 B = 30, A = (130 - 3×30)/2 = 20 Therefore, difference between A and B = 30 - 20 = 10Submit Quiz123456Next »