Solution:त्रिज्या (r) =d/2 =0.3/2 =0.15 mm
A=∏r² =22 × 0.15 × 0.15 =0.07 mm²
यहाँ R = 50 Ω, L = 1m, A = 0.07 mm²
R =ρ L/A
ρ= R× A/L = 50 × 0.07/1 × 10³=0.0035 Ω mm
शर्त ॥ - त्रिज्या (r) =d/2 =0.6/2 =0.3mm
A = ∏r² =22×0.6× 0.6/7×2×2 =0.28~mm²
यहाँ ρ =0.0035 Ω mm), L = 1m, A = 0.28
R=ρ L/A = 0.0035 × 10³/0.28 =12.5 Ω