Algebra (Mathematics Chapterwise Solved Papers for Teaching) (Part-2)Theory of Equation and InequationsTotal Questions: 5041. Solve the following equation? [OAVS TGT 2021](a) 11/30(b) 29/30(c) 19/30(d) 21/30Correct Answer: (a) 11/30Solution:42. Solve the following question? [OAVS TGT 2021](a)(b)(c)(d)Correct Answer: (c)Solution:43. The quadratic polynomial whose sum of zeroes is 6 and product of zeroes is β16 is: [OAVS TGT 2021](a) xΒ²-16π-6(b) πΒ² +16π+6(c) πΒ²-6π-16(d) πΒ² +16π-6Correct Answer: (c) πΒ²-6π-16Solution:If sum of zeros = 6 i.e. Ξ±+Ξ² = 6 & product of zeros =-16 i.e. Ξ± Ξ² = -16 Where, Ξ±, Ξ² are the zeros of polynomial. Then, quadratic polynomial = πΒ² - (Ξ±+Ξ²)π + Ξ±Ξ² = πΒ² - 6π -1644. If the difference between the roots of the equation πΒ² + 2kπ+1 = 0 is less than 2β3, then _______ is the set of possible values of k. [OAVS TGT 2021](a) (-2, 0)(b) (-2, 2)(c) (2, β)(d) (-β,-2)Correct Answer: (b) (-2, 2)Solution:45. What is the value of 10mΒ³ + 3mΒ² - 5m - 279 if (2m, -m) is a solution of 15π + 13y =51? [OAVS TGT 2021](a) 3(b) 2(c) 1(d) 4Correct Answer: (a) 3Solution:46. If P(k) be the statement that 'A' set with elements has 2α΅ subsets', then for P(0), the number of subsets are: [OAVS TGT 2021](a) 3(b) 1(c) 0(d) 2Correct Answer: (b) 1Solution:If P(k) is statement such that 'A' set with elements has 2α΅ subjects. Then for P(0), the number of subsets will be 2β°, = 147. The degree of the polynomial π (π+ 2) (πΒ³-π+πβ΄+3) is [OAVS TGT 2021](a) 3(b) 6(c) 4(d) 5Correct Answer: (b) 6Solution:Given f(π) = π (π+ 2) (πΒ³-π+πβ΄+3) i.e. f(π) = π(π+2) (πβ΄+πΒ³-π+3) Degree of polynomial = highest power of πΒ in above polynomial. i.e. degree = 648. If 2πβ΄ - aπΒ³ - bπΒ² + cπ - 3, divided by π -2 leaves a remainder of 5, divided by π + 2 leaves remainder 29, what is the value of b? [OAVS TGT 2021](a) 3(b) 2(c) 5(d) 4Correct Answer: (a) 3Solution:49. Solution of the absolute value of inequality 3|3π+9| <54 is: [OAVS TGT 2021](a) -9<π< 3(b) -3<π<9(c) -9<π<-3(d) 36Correct Answer: (a) -9<π< 3Solution:50. πΒ²-3π+|m|= 0 has real roots. How many integer values can m take? [OAVS TGT 2021 ](a) 7(b) 5(c) 3(d) 4Correct Answer: (b) 5Solution:Submit Quiz« Previous12345