Algebra (Mathematics Chapterwise Solved Papers for Teaching) (Part-4)Theory of Equation and InequationsTotal Questions: 5031. Solve the following equation? [UKPSC Lecturer (Mains) 2020](a) 1(b) 53/49(c) 50/39(d) 59/37Correct Answer: (b) 53/49Solution:32. Solve the following equation? [UKPSC Lecturer (Mains) 2020] (a) 𝓍 >18(b) 𝓍 >16(c) 𝓍 >14(d) 𝓍 >12Correct Answer: (b) 𝓍 >16Solution:33. The number of values of 'a' for which the system of equations [UKPSC Lecturer (Mains) 2020](a+1) 𝓍+8y = 4a a𝓍+ (a+3) y = 3a - 1 has infinitely many solutions is :(a) 2(b) 1(c) 0(d) infiniteCorrect Answer: (b) 1Solution:For infinitely many solutions of the given system of linear equations we must have 34. The inequality 7𝓍²+11>𝓍³ +17𝓍 is satisfied for all values of 𝓍 which satisfy the following: [UKPSC Lecturer (Mains) 2020](a) 0<𝓍<1(b) 1∞(c) -∞<𝓍<1(d) -1<𝓍<1Correct Answer: (c) -∞<𝓍<1Solution:35. The number of values of k for which the linear equations 4𝓍+ky+2z = 0; k𝓍+4y+z = 0; 2𝓍+2y+z = 0 possess a non-zero solution is: [Haryana PGT 2019](a) 2(b) 1(c) zero(d) 3Correct Answer: (a) 2Solution:36. If the difference between the roots of the equation 𝓍²+a𝓍+1 = 0 is less than √5, then the set of possible values of 'a' is: [Haryana PGT 2019](a) (-3,3)(b) (-3,∞)(c) (3,∞)(d) (-∞,-3)Correct Answer: (a) (-3,3)Solution:37. Solve the following equation? [Haryana TGT 2020](a) 2(b) 1(c) 0(d) -2Correct Answer: (a) 2Solution:38. The pair of equation y = 0 and y = 5 has solutions: [Haryana TGT 2020](a) One solution(b) Two solution(c) no solution(d) Infinitely many solutionsCorrect Answer: (c) no solutionSolution:The pair of equation y = 0 and y = 5 has no solution because they are parallel pair of lines.39. If -2 and 3 are the zeroes of the quadratic polynomial 𝓍²+(a+1) 𝓍+b, then: [Haryana TGT 2020](b) a = -2; b = -6(a) a = 2; b = 6(c) a = -2; b = 6(d) a = 2; b = -6Correct Answer: (b) a = -2; b = -6Solution:40. If one of the zeros of the polynomial 𝓍³+ a𝓍²+ b𝓍 + c is -1, then the product of other two zeros is equal to: [Haryana TGT 2019](a) b-a+1(b) b-a-1(c) a-b+1(d) a-b-1Correct Answer: (a) b-a+1Solution:Submit Quiz« Previous12345Next »