Solution:For the quadratic equation to have real roots, the discriminant must be greater than or equal to zero.
For the first equation k² - 4(1)(64) > 0
(discriminant = b² - 4ac) ⇒ k² - 256 > 0
⇒ (k - 16) (k + 16) > 0 ⇒ k > 16 and k < -16 For the second equation
64 - 4k > 0 ⇒ k < 16
The value of K that satisfies both the condition is k = 16