Analogy varieties Question TCS (Part – I)

n : {(n + 8) × 8}
(25 : 264) → {(25 +8) × 8} = 264
(49 : 456) → {(49 + 8) × 8} = 456
Similarly,

(31 : ?) → {(31 + 8) × 8} = 312

Hence, 312 is the correct answer.

(Difference between the given number cluster is 75)
(687 : 612) → 687 - 612 = 75
(621 : 546) → 621 - 546 = 75
Similarly, let ? = y

(713 : y) → 713 - y = 75

y = 713 - 75

y = 638

Hence, 638 is the correct answer.

a : (a³ - 2 × a)
(8 : 496) → (8³ - 2 × 8) = 496
(9 : 711) → (9³ - 2 × 9) = 711

Similarly,

(6 : 204) → (6³ - 2 × 6) = 204

Hence, 6 is the correct answer.

n : {(n + 7) × 7}
(21 : 196) → {(21 + 7) × 7} = 196
(38 : 315) → {(38 + 7) × 7} = 315
Similarly,

(29 : 252) → {(29 + 7) × 7} = 252

Hence, 252 is the correct answer.

n : {n² + (n × 11)}
(24 : 840) → {24² + (24 × 11)} = 840
(33 : 1452) → {33² + (33 × 11)} = 1452
Similarly,

(27 : 1026) → {27² + (27 × 11)} = 1026

Hence, 1026 is the correct answer.

{(1^st number × 3) - 11} = 2^nd number
(37 : 100) → {(37 × 3) - 11} = 100
(29 : 76) → {(29 × 3) - 11} = 76
Similarly,

(24 : 61) → {(24 × 3) - 11} = 61

Hence, 61 is the correct answer.

(a : b) → ( a ÷ 3)² = b

(12 : 16) → (12 ÷ 3)² = 16

(24 : 64) → (24 ÷ 3)² = 64

Similarly,

(18 : ?) → (18 ÷ 3)² = 36

Hence, 36 is the correct answer.

[{(1st number)³ + (3rd number)³}÷ 2] = 2nd number
(3, 14, 1) → (3³ + 1³) ÷ 2 = 14
(4, 36, 2) → (4³ + 2³) ÷ 2 = 36
Similarly,
(8, 260, 2) → (8³ + 2³) ÷ 2 = 260

Hence, (8, 260, 2) is the correct answer.

{(1^st number × 2) + 2^nd number} = 3^rd Number
(5, 60, 70) → {(5 × 2) + 60} = 70
(9, 108, 126) → {(9 × 2) + 108} = 126
Similarly,

(7, 84, 98) → {(7 × 2) + 84} = 98

Hence, (7, 84, 98) is the correct answer.

Hence, 1/80 is the correct answer.