AREA AND PERIMETER (CDS)Total Questions: 11631. There is a path of width 5 m around a circular plot of land whose area is 144π m². The total area of the circular plot including the path surrounding it is [2018 (II) Evening Shift](a) 349π m²(b) 289π m²(c) 209π m²(d) 149π m²Correct Answer: (b) 289π m²Solution:Area of circular, Plot of land = 144π m²32. An equilateral triangle, a square and a circle have equal perimeter. If T S, and C denote the area of the triangle, area of the square and area of the circle respectively, then which one of the following is correct? [2018 (II) Evening Shift](a) T < S < C(b) S < T < C(c) C < S < T(d) T < C < SCorrect Answer: (a) T < S < CSolution:An equilateral triangle, a square and a circle of perimeter are equal 33. The areas of two similar triangles are (7 - 4√3) cm² and (7 + 4√3) cm² respectively. The ratio of their corresponding sides is [2018 (II) Evening Shift](a) 7 - 4√3(b) 7 - 3√3(c) 5 - √3(d) 5 + √3Correct Answer: (a) 7 - 4√3Solution:Ratio of area of two similar triangle = Ratio of square of their corresponding sides34. The area of the region bounded internally by a square of side 2a cm and externally by the circle touching the four sides of the square is(a)(b)(c)(d)2018 (II) Evening ShiftCorrect Answer: (a)Solution:Side of square ABCD is 2a cm35. In the figure given below, ABC is a right-angled triangle where ∠A = 90º, AB = p cm and AC = q cm. On the three sides as diameters semi-circles are drawn as shown in the figure. The area of the shaded portion, in square cm, is [2018 (II) Evening Shift](a)(b)(c)(d)Correct Answer: (d)Solution:36. In the figure given below, ABCD is the diameter of a circle of radius 9 cm. The lengths AB, BC and CD are equal. Semi-circles are drawn on AB and BD as diameters as shown in the figure. What is the area of the shaded region? [2018 (II) Evening Shift](a) 9π(b) 27 π(c) 36π(d) 81πCorrect Answer: (b) 27 πSolution:Area of shaded regions = Area of semi-circle on AD + area of semicircle on AB – area of semi-circle on BD37. In the figure given below, the diameter of bigger semi-circle is 108 cm. What is the area of the shaded region? [2018 (II) Evening Shift](a) 201 π cm²(b) 186.3 π cm²(c) 405 π cm²(d) 769.5 π cm²Correct Answer: (c) 405 π cm²Solution:Given, AO = OB = OD = 54cm 38. In the figure given below, ABCD is a square of side 4 cm. Quadrants of a circle of diameter 2 cm are removed form the four corners and a circle of diameter 2 cm is also removed. What is the area of the shaded region? [2018 (II) Evening Shift](a) 5⁷⁄₉(b) 7⁷⁄₉(c) 9⁵⁄₇(d) 9⅚Correct Answer: (c) 9⁵⁄₇Solution:Area of shaded region = Area of square – 4 (area of quadrant)– area of circle 39. Walls (excluding roofs and floors) of 5 identical rooms having length, breadth and height 6 m, 4 m and 2.5 m respectively are to be painted. Out of five rooms, two rooms have one square window each having a side of 2.5 m. Paints are availbable only in cans of 1 L; and 1 L of paint can be used for painting 20 m² . The number of cans required for painting is [2018 (II) Evening Shift](a) 10(b) 12(c) 13(d) 14Correct Answer: (b) 12Solution:Length (l), breadth (b) and height (h) of walls are 6 m, 4m and 2.5 m respectively,40. Two equal circular regions of greatest possible area are cut off from a given circular sheet of area A. what is the remaining area of the sheet? [2018 (I) Morning Shift](a) A/2(b) A/3(c) 3A/5(d) 2A/5Correct Answer: (a) A/2Solution:Let the radius of circular sheet be ‘R’ Submit Quiz« Previous123456789101112Next »