Correct Answer: (d) 6 /14 C , 7 /15 N , 8 /16 O 6 /14 C, 7 /15 โ N, 8 /16 O
Note: Two nuclides are isoneutronic (isotones) if they have the same neutron number NNN, but a different proton number ZZZ.
For example, Boron-12 and Carbon-13 nuclei both contain 7 neutrons and are thus isotones.
As per the question:
- 614C^{14}_{6}\text{C}614โC โ 14โ6=814 - 6 = 814โ6=8 neutrons
- 715N^{15}_{7}\text{N}715โN โ 15โ7=815 - 7 = 815โ7=8 neutrons
- 816O^{16}_{8}\text{O}816โO โ 16โ8=816 - 8 = 816โ8=8 neutrons
Since the number of neutrons in all is 8, they are all isotones.