BANK & INSURANCE (AGE BASED PROBLEMS) PART 2

Let the father age be 'x' years and son age be 'y' years

Given, The sum of the ages of father and his son is 45 years.

x + y = 45

⇒ y = 45 − x ...(i)

Given, 5 years ago, the product of their ages was 34

(x − 5) × (y − 5) = 34 ...(ii)

From (i) and (ii),

⇒ (x − 5)(45 − x − 5) = 34

⇒ (x − 5)(40 − x) = 34

⇒ 40x − x² − 200 + 5x = 34

⇒ −x² + 45x − 200 − 34 = 0

⇒ x² − 45x + 234 = 0

⇒ x² − 39x − 6x + 234 = 0

⇒ x(x − 39) − 6(x − 39) = 0

⇒ (x − 6)(x − 39) = 0

⇒ x = 6, 39

Therefore, father's age is 39 years and Son's age is 6 years.

Let the present age of John be x and that of his son be y

Forming equations

x − 5 = 5(y − 5)

x + 5 = 3(y + 5)

After solving we get

x = 55 and y = 15

After how many years, he will be twice as old as son

55 + x = 2(15 + x)

x = 25 years

The answer can be found by trying options

(55 + 25) / (15 + 25) = 2

Let the present age of Ravi be x

As,

Ravi's tenth birthday was celebrated three years.

So,

his present age = 10 + 3 = 13 years

Ravi's age after 10 years = 10 + 13 = 23 years

Let Shiva and Vijay's age be S and V respectively.

Then,

v + 10 = 2 × (10 + x)

⇒ v + 10 = 20 + 2x

⇒ v + 10 = 20 + 2 × 23

⇒ v = 46 − 10

⇒ v = 36

∴ Age of Shiva = 1/6 × 36 = 6 years

Let there are n no. of males

(n + 15) × 18 = 240 + 20n

n = 15

Let A = Anup's age, M = Mahesh's age, S = Shyam's age

(S − 6) / 18 = A

Also, A = 3 years (Therefore, M = 5 years)

S = 3 × 18 + 6 = 60 years