BANK & INSURANCE (SPEED TIME AND DISTANCE) PART 3

Total Questions: 45

41. The speed of faster train is what percentage of the speed of slower train on Monday?

Correct Answer: (d) 164 % 
Solution:

The speed of train P = 450/9 = 50 Km/hr
The speed of train Q = 640/8 = 80 Km/hr
The speed of train R = 820/10 = 82 Km/hr
The speed of train S = 780/13 = 60 Km/hr
The speed of train T = 960/12 = 80 Km/hr
The speed of train U = 840/14 = 60 Km/hr

The speed of faster train = 82 Km/hr
The speed of slower train = 50 Km/hr

Required % = (82/50) × 100 = 164 %

42. If the speed of train T is increased by 20 % and the speed of the train S is increased by 25 % on Tuesday while comparing with Monday, then the speed of train T on Tuesday is what percentage of the speed of train S on Tuesday?

Correct Answer: (b) 128 % 
Solution:

The speed of train T on Monday = 960/12
= 80 Km/hr

The speed of train T on Tuesday = 80 × (120/100)
= 96 Km/hr

The speed of train S on Monday = 780/13
= 60 Km/hr

The speed of train S on Tuesday = 60 × (125/100)
= 75 Km/hr

Required % = (96/75) × 100 = 128 %

43. If the total distance covered by train A on Monday is 40 % more than the total distance covered by train T on Monday and the time taken by train A to reach the destination is double the time taken by train T to reach the destination, then find the speed of train A?

Correct Answer: (c) 56 Km/hr
Solution:

The total distance covered by train A on Monday
=> 960 × (140/100) = 1344 Km

The time taken by train A to reach the destination
=> 2 × 12 = 24 hr

The speed of train A = Distance/Time = 1344/24
= 56 Km/hr

44. Find the ratio between the speed of train P, R and T together to that of train Q, S and U together?

Correct Answer: (b) 53: 50 
Solution:

The speed of train P = 450/9 = 50 Km/hr
The speed of train Q = 640/8 = 80 Km/hr
The speed of train R = 820/10 = 82 Km/hr
The speed of train S = 780/13 = 60 Km/hr
The speed of train T = 960/12 = 80 Km/hr
The speed of train U = 840/14 = 60 Km/hr

The speed of train P, R and T together
=> (450/9) + (820/10) + (960/12)
= 50 + 82 + 80 = 212 Km/hr

The speed of train Q, S and U together
=> (640/8) + (780/13) + (840/14)
= 80 + 60 + 60 = 200 Km/hr

Required ratio = 212 : 200 = 53 : 50

45. A boat can cover 42 km upstream in 63 minutes. If the speed of the current is 3/7 of the boat in still water, then how much distance (in km) can the boat cover downstream in 42 minutes?

Correct Answer: (a) 70 km 
Solution:

Speed of upstream = (42 × 60)/63 = 40 km/hr

Speed of current : Speed of still water = 3 : 7

Speed of upstream = Speed of boat in still water - speed of Current
40 = 4x
=> x = 10

Speed of current = 30 km/hr
Speed of boat in still water = 70 km/hr

Speed of downstream = Speed of boat in still water + speed of Current
=> 70 + 30 = 100 km/hr

Speed = 100 km/hr, Time = 42 minutes
Distance = 100 × (42/60) = 70 km