BANK & INSURANCE (NEW PATTERN SERIES)

Total Questions: 50

41. Which of the following relations among P, Q and R is/are true?

A. P² + R² = Q
B. PQ/R = P + Q + 60
C. 2PR = Q

Correct Answer: (c) Only A
Solution:

P = 12, Q = 225, R = 9

From A:
P² + R² = Q
144 + 81 = 225
So, A is true.

From B:
PQ/R = P + Q + 60
(12 × 225)/9 = 12 + 225 + 60
300 = 297
So, B is not true.

From C:
2PR = Q
2 × 12 × 9 = 225
216 = 225
So, C is not true.

42. The question given below consists of a number series I formed with some logic. In the given series I, one number is wrong. Find that wrong number and make the number series II (following the same logic as by series I) by taking the identified wrong number as the first element of series II.

Number series I: 3, 4.5, 13.5, 38, 156.5, 788, 4734.5

What is the difference between the 3rd and 6th element of number series II?

Correct Answer: (b) 2015.5
Solution:

Logic for number series I:
3 × 1 + 1.5 = 4.5
4.5 × 2 + 2.5 = 11.5
11.5 × 3 + 3.5 = 38
38 × 4 + 4.5 = 156.5
156.5 × 5 + 5.5 = 788
788 × 6 + 6.5 = 4734.5

So, wrong number in series I = 13.5

Now, 13.5 is the first element of series II and the its other elements will be:

2nd element: 13.5 × 1 + 1.5 = 15
3rd element: 15 × 2 + 2.5 = 32.5
4th element: 32.5 × 3 + 3.5 = 101
5th element: 101 × 4 + 4.5 = 408.5
6th element: 408.5 × 5 + 5.5 = 2048

Therefore, difference 3rd and 6th element of series II
= 2048 − 32.5 = 2015.5

43. Given below are two series I and II, having missing terms (p) and (q). Answer the question that follows.

Series I: 3, 4, (p), 33, 136, 685
Series II: 19, 24, 17, 28, (q), 32

Man invested Rs.8000 in scheme A for 3 years at (P)% annual CI and Rs.5296 in scheme B for ‘t’ years at (p + q)% SI. If the interest amount from both the schemes is same, then what is the value of ‘t’?

Correct Answer: (d) 2 years
Solution:

Series I:
3 × 1 + 1 = 4
4 × 2 + 2 = 10 = p
10 × 3 + 3 = 33
33 × 4 + 4 = 136
136 × 5 + 5 = 685

Series II:
19 + 5 = 24
24 − 7 = 17
17 + 11 = 28
28 − 13 = 15 = q
15 + 17 = 32

Interest amount from scheme A = 8000 × [(1.1)³ − 1] = Rs.2648

Interest amount from scheme B = (5296 × t × 25)/100 = 2648

t = 2 years

44. Given below is the sequence of series. Analyse the pattern of the series and answer the given following questions.

2, 10, 33, 68, 115, ..., 670.

If 376 is the nth term, then what is the value of n?

Correct Answer: (d) 8
Solution:

The logic in the given series is:

1 × 2 = 2
2 × 5 = 10
3 × 11 = 33
4 × 17 = 68
5 × 23 = 115
6 × 31 = 186
7 × 41 = 287
8 × 47 = 376
9 × 59 = 531
10 × 67 = 670

Therefore, 376 is the 8th term in the series.
Hence, n = 8

45. Below given are three series I, II and III and all the series follow different logic.

 Series I: 12, 16, 32, (P + 4), 132, 232
Series II: 720, 720, 360, (Q - 1), 30, 6
Series III: 27, 125, (R + 19), 729, 1331

Among P, Q and R which are perfect squares?

Correct Answer: (c) All P, Q, and R
Solution:

Series I: 12, 16, 32, (P + 4), 132, 232

Logic in the series is:
12 + 2² = 16
16 + 4² = 32
32 + 6² = 68 = (P + 4) => P = 64
68 + 8² = 132
132 + 10² = 232

Series II: 720, 720, 360, (Q − 1), 30, 6

Logic in the series is:
720 ÷ 1 = 720
720 ÷ 2 = 360
360 ÷ 3 = 120 = (Q − 1) => Q = 121
120 ÷ 4 = 30
30 ÷ 5 = 6

Series III: 27, 125, (R + 19), 729, 1331

Logic in the series is:
3³ = 27
5³ = 125
7³ = (R + 19) => R = 324
9³ = 729
11³ = 1331

√P = √64 = 8
√Q = √121 = 11
√R = √324 = 18

Hence, all are perfect squares

46. In the following question, initially a series of numbers is given and one of which is a wrong number. A similar logic is applied in the second series with blanks.

Find the wrong number in the first series and the number which comes in the place of '?' in the second series respectively.

16, 72, 216, 488, 874.8, 1312.2
48, ___, ?

Correct Answer: (b) 488 and 3936.6
Solution:

Logic in the first series:
16 × (9/2) = 72
72 × (9/3) = 216
216 × (9/4) = 486 (Wrong term)
486 × (9/5) = 874.8
874.8 × (9/6) = 1312.2

Similarly,
48 × (9/2) = 216
216 × (9/3) = 648
648 × (9/4) = 1458
1458 × (9/5) = 2624.4
2624.4 × (9/6) = 3936.6

47. Below given are two series I and II both the series follow a certain pattern. All the two series have some missing terms, find the value of missing terms, and answer the following questions.

Series I: 241, 340, P, 571, 703, 846
Series II: 876, 777, 689, 612, Q, 491

Which of the following is not the factor of difference between values of P and Q?

Correct Answer: (b) 18
Solution:

Series I: 241, 340, P, 571, 703, 846

Logic in the series is:

241 340 450 571 703 846
+99 +110 +121 +132 +143
+11 +11 +11 +11

P = 450

Series II: 876, 777, 689, 612, Q, 491

Logic in the series is:
876 − 99 = 777
777 − 88 = 689
689 − 77 = 612
612 − 66 = 546
546 − 55 = 491

Q = 546

Difference between P and Q = 546 − 450 = 96

Factors of 96 = 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, and 96.

Hence, 18 is not the factor of 96.

48. Directions (48-49): Below given are two series I and II and both the series follow the same pattern. First term of series II is given and series I contains one wrong term in it which is identified as A.

Series I: 112, 56, 84, 210, 735, 2940
Series II: 32, __, __, __, __, __

48. If 'm' is the 3rd term of series II and 'n' is the 5th term of series II, then what is the following TRUE?

Correct Answer: (d) n ÷ m = 8.75
Solution:

Series I: 112, 56, 84, 210, 735, 2940

Logic in the series:
112 × 0.5 = 56
56 × 1.5 = 84
84 × 2.5 = 210
210 × 3.5 = 735
735 × 4.5 = 3307.5 (Not 2940)

A = 2940

Series II: 32, __, __, __, __

32 × 0.5 = 16
16 × 1.5 = 24
24 × 2.5 = 60
60 × 3.5 = 210
210 × 4.5 = 945

Series II: 32, 16, 24, 60, 210, 945

m = 24
n = 210
n ÷ m = 8.75

49. Wrong term of series I is how many times of 6th term of series II?

Correct Answer: (d) 28/9
Solution:

Series I: 112, 56, 84, 210, 735, 2940

Logic in the series:
112 × 0.5 = 56
56 × 1.5 = 84
84 × 2.5 = 210
210 × 3.5 = 735
735 × 4.5 = 3307.5 (Not 2940)

A = 2940

Series II: 32, __, __, __, __

32 × 0.5 = 16
16 × 1.5 = 24
24 × 2.5 = 60
60 × 3.5 = 210
210 × 4.5 = 945

Series II: 32, 16, 24, 60, 210, 945

Wrong term of series I = 2940
6th term of series II = 945

Required answer = 2940/945 = 28/9

50. Below given is a series I with one wrong term. Another series II starts with the wrong term of series I and follows the same pattern of series I.

Series I: 7, 15, 35, 67, 138, 281, 568

If the 3rd term of series II is equal to N, then which of the following statement(s) is/are correct?

I. Wrong term of series I and N are co-prime to each other.

II. If one root of equation x² - px + N = 0 is 18, the value of p is 8.

III. Unit digit of 19^N is 9.

Correct Answer: (c) Only I
Solution:

Logic in the series I is:

7 × 2 + 1 = 15
15 × 2 + 2 = 32 (Not 35)
32 × 2 + 3 = 67
67 × 2 + 4 = 138
138 × 2 + 5 = 281
281 × 2 + 6 = 568