BANK & INSURANCE (PERCENTAGE) PART 1Total Questions: 6041. Shobha's Mathematics test had 75 problems i.e. 10 arithmetic, 30 algebra and 35 geometry problems. Although she answered 70% of the arithmetic, 40% of the algebra and 60% of the geometry problems correctly, she did not pass the test because she got less than 60% of the problems right. How many more questions she would have needed to answer correctly to earn a 60% passing grade?(a) 2 (b) 4(c) 5(d) 7 (e) None of theseCorrect Answer: (c) 5Solution:Number of questions attempted correctly = (70% of 10 + 40% of 30 + 60% of 35) ⇒ (7 + 12 + 21) = 40. Questions to be answered correctly for 60% grade = 60% of 75 = 45. So, Required number of questions = (45 - 40) = 5.42. Fourty-five percent of a number is 30 less than three-fifth of that number. What is the number?(a) 100 (b) 120 (c) 130(d) 200 (e) None of theseCorrect Answer: (d) 200 Solution:Let the number be x. Then, (3x/5) - (45% of x) = 30 ⇒ (3x/5) - (45x/100) = 30 ⇒ 15x = 3000 ⇒ x = 200.43. Mr. Keisham gave 40% of the money he had, to his wife. He also gave 20% of the remaining amount to each of his three sons, Half of the amount now left was spent on miscellaneous item and the remaining amount of Rs. 12,000 was deposited in the bank. How much money did Mr. Keisham have initially?(a) 1,000 (b) 10,000 (c) 1,00,000(d) 10,00,000 (e) None of theseCorrect Answer: (c) 1,00,000Solution:Let the initial amount with Mr. Keisham be Rs. x. Then, ½ [100 - (3 × 20)]% of (100 - 40)% of x = 12000⇒ ½ × 40/100 × 60/100 × x = 12000 ⇒ 3/25 × x = 12000 ⇒ x = 12000 × 25 / 3 = 10000044. When the price of a product was decreased by 10%, then the number of sell increased by 30%. What was the effect on the total revenue?(a) 5% (b) 10% (c) 12%(d) 17% (e) None of theseCorrect Answer: (d) 17% Solution:To solve this question, we can apply a short trick approach; Net% effect = (x + y + xy/100)% Increase or decrease, according to the +ve or -ve sign respectively. Given; Price Increased = x = 30% Price Decreased = y = - 10% By the short trick approach, we get = (30 - 10 - 30 × 10/100) = 17%45. If the numerator of a fraction be increased by 15% and its denominator be diminished by 8%, the value of the fraction is 15/16. Find the original fraction.(a) 1/2 (b) 3/2 (c) 3/4(d) 4/3 (e) None of theseCorrect Answer: (c) 3/4Solution:Let the original fraction be x/y Then, 115% of x / 92% of y = 15/16 ⇒ 115x / 92y = 15/16 ⇒ x/y = 15/16 × 92/115 = 3/446. The population of a town is 1,76,400. If it increase at the rate of 5% per annum, what will be its population 2 years hence? What was it 2 years ago?(a) 1,94,481 and 1,60,000 (b) 1,43,564 and 1,20,000(c) 1,56,342 and 2,00,000 (d) 3,22,968 and 3,40,000(e) None of theseCorrect Answer: (a) 1,94,481 and 1,60,000 Solution:Population after 2 years = 176400 × (1 + 5/100)² = 194481 Population 2 years ago = 176400 / (1 + 5/100)² = 16000047. In the new budget, the price of refined oil rose by 25%. By how much percent must a person reduce his consumption so that his expenditure on it does not increase?(a) 10% (b) 20% (c) 25%(d) 30% (e) None of theseCorrect Answer: (b) 20% Solution:Where R => the rose price of refined oil = 25% Reduction in consumption = [R / (100 + R) × 100%] ⇒ (25 / 125 × 100) % = 20%48. Deepika's salary was decreased by 50% and subsequently increased by 50%. How much percent does she lose?(a) 5% (b) 10% (c) 15%(d) 25% (e) None of theseCorrect Answer: (d) 25% Solution:To solve this question, we can apply a short trick approach; Net% effect = (x + y + xy/100)% Increase or decrease, according to the +ve or -ve sign respectively. Given; Increased Number = x = 50% Decreased Number = y = - 50% By the short trick approach, we get = (50 - 50 - 50 × 50/100) = -25%49. The monthly income of a person was reduced by 10%. By what percent should his reduced monthly income be raised so as to bring it at par with his original income?(a) 9 1/9 % (b) 15% (c) 11 1/9 %(d) 8 1/3 % (e) None of theseCorrect Answer: (c) 11 1/9 %Solution:Let the original monthly income be Rs. 100, New income = Rs. 90. Increase on 90 (new income) = 10. Then, Increase on 100 = (10/90 × 100)% = 11⅑%50. Virat spent 14% of his income on electricity bills, 28% on rent and 18% on shopping. ¼ of the remaining amount is Rs. 5125. How much did he spend on electricity bill?(a) 7175 (b) 7170 (c) 7372(d) 7270 (e) None of theseCorrect Answer: (a) 7175 Solution:Remaining = 100x - (14x + 28x + 18x) = 40x Amount = ¼ × 40x = 5125 x = 512.5 Electricity Bill = 512.5 × 14 = 7175Submit Quiz« Previous123456Next »