BANK & INSURANCE (PERCENTAGE) PART 2

Total Questions: 60

41. The price of rice has increased by 20%. Lalu has decided to spend only 8% more than what he initially did on buying rice. What is the percentage decrease in Lalu's rice consumption?

Correct Answer: (a) 10% 
Solution:Let the initial price of Lalu be Rs. 100 per unit and Lalu’s consumption be 10 units.
∴ Initial amount spent = 100 × 10 = Rs. 1,000
New price of rice = 120% of 100 = Rs. 120 and new total amount spent = 108% of 1000 = Rs. 1,080
∴ New consumption = 1080/120 = 9 units
∴ Decrease in consumption = 1 unit
∴ % decrease = 1/10 × 100 = 10%

42. The production of a company has ups and downs every year. The production increases for two consecutive years consistently by 15% and in the third year it decreases by 20%. Again in the next two years it increases by 25% each year and decreases by 10% in the third year. If we start counting from the year 2014 approximately what will be the effect on the production of the Company in 2018?

Correct Answer: (b) 32 
Solution:

Suppose the production of the company in the year 2014 be x.
Then production of the company in year 2018
= x × 115/100 × 115/100 × 80/100 × 125/100
= 1.32x
∴ Increase % in the production in year 2018
= (1.32x − x)/x × 100 = 32%

43. In a village, two contestants (A & B) are contesting in an election. 70% of the registered voters cast their votes in the election and A wins the election by 400 votes. If A had received 12.5% less votes, A’s votes would have been equal to B’s votes. How many registered voters are there in the village?

Correct Answer: (c) 4000
Solution:

Let the votes received by A & B be x and y respectively.
Now as per the given statements, x − y = 400 …(1)
Also (87.5/100) x = y + (12.5/100)x …(2)
(The votes lost by A would go into B's account)
solving (2), we get
y = 3x/4 …(3)
Using (3) to solve (1) we get
x − 3x/4 = 400
x = 1600 And, y = 1200
Now, we know that A & B collectively won 70% of total votes.
If the total number of registered voters in the village be Z,
Then, (70z/100) = 1600 + 1200 = 2800
Z = 4000

44. A person had a certain amount. He invested 5/6th of it in shares, 5% of it in mutual funds, 10% of it in debentures and kept the remaining Rs. 850 with him. If got interest at 10% for a year on debentures, what amount did he get as interest?

Correct Answer: (c) Rs. 510
Solution:5/6 corresponds to 83.33%.
Hence, the amount that he kept with him corresponds to
100 − (83.33 + 5 + 10) = 1.67% of the total amount with him.
This corresponds to Rs. 850 Also, because he placed 10% in debentures and he got 10% interest, amount obtained in interest = 10% of 10% of amount with him i.e. 1% of the amount with him.
∴ Interest earned = (850 × 1)/1.67 = 510

45. A car costing Rs. 5,00,000 of a person depreciated at the rate of 15% in the first year, 13% in the second year and so on. House of that person, costing Rs. 7,00,000 appreciated at the rate of 10% in the first year, 12% in the second year and so on. What was the change in total value of car, house at the end of 3 years?

Correct Answer: (c) Increase of Rs. 1,12,214
Solution:Original cost of a car and house = 500000 + 700000 = Rs. 12,00,000
New cost of car = 500000 × 0.85 × 0.87 × 0.89 = Rs. 329077.5
New cost of house = 700000 × 1.1 × 1.12 × 1.14
= Rs. 983136
∴ Total new cost = Rs. 13,12,213.5
∴ Change = increase of Rs. 1,12,213.5 ≈ Rs. 1,12,214

46. The ratio of Ashok's to Bhanu's earnings is 4:9. If Bhanu's earnings is increased by 45%, then his total earnings becomes Rs. 33930.What is the earning of Ashok?

Correct Answer: (e) None of these
Solution:Let the salary of Ashok to Bhanu be 4x and 9x respectively.
Then, 9x × 145/100 = 33930
⇒ 9x × (33930 × 100)/(9 × 45) = 2600
∴ Ashok's salary = 4x = 4 × 2600 = 10400

47. The marks scored by Prasoon Joshi in three subjects are in the ratio 4 : 5 : 6. Prasoon Joshi scored an overall aggregate of 60% in the exam. If the maximum marks in each subject are the same, in how many subjects did Prasoon Joshi score more than 70% marks?

Correct Answer: (a) One 
Solution:

Let the maximum marks in each subject be 100.
∴ Prasoon joshi’s total score
= 60% of (100 + 100 + 100)
= 0.6 (300) = 180
Also, 70% marks in a subject correspond to 0.7(100)
= 70
Let Prashoon joshi have scored 4x, 5x and 6x in the three subjects.
∴ 4x + 5x + 6x = 180
∴ 15x = 180 i.e. x = 12
Hence, his marks in the three subjects are 48, 60 and 72
Hence, he has scored more than 70 in exactly one subject.

48. On reducing the entry fee by 35% in a park, the number of people coming to the park increased by 40%, then the percent increase or decrease in the income from the entry fee is –

Correct Answer: (c) 9% decrease
Solution:

Let the original entry fee be ‘a’ and number of people initially coming to the park be ‘b’.
Total income = a × b = ab
Now, reducing the entry fee by 35% in a park, the number of people coming to the park increased by 40%

⇒ New entry fee = a − 35% of a = 0.65a
Number of people = b + 40% of b = 1.4 b
Total income = 0.65a × 1.4b = 0.91 ab
Decrease in income = ab − 0.91ab = 0.09ab
% decrease in income = (0.09ab/ab) × 100
⇒ % decrease in income = 9%

49. In a coaching there are 3 batches namely lolos,momos and joojos. Out of the total students in the coaching there are 25%, 35% and 40% students in these batches respectively. If 2%, 4% and 5% students of respective batches passes then what is the percentage of failed students?

Correct Answer: (d) 96.1% 
Solution:Let total number of students in the coaching be x
Then number of student in lolos batches = 25% of x = 0.25x
number of student in momos batches = 35% of x = 0.35x
number of student in jojo’s batches = 40% of x = 0.40x
number of passed students in lolos batches = 2% of 0.25x = 0.005x
number of passed students in momos batches = 4% of 0.35x = 0.014x
number of passed students in jojo’s batches = 5% of 0.40x = 0.02x
so total number of passed students = 0.005 + 0.014x + 0.02x = 0.039x
therefore number of failed students = Total number of students − total number of passed students
= x − 0.039x = 0.961x
Hence the percentage of failed students
= (0.961x/x)×100 = 96.1%

50. In a nuclear reaction, two particles A and B are formed at the different rate every microsecond. When time is 0 microsecond, the ratio of particle A to particle B was 4 : 5 but when t = 1 microsecond, the ratio of particle A to particle B becomes 5 : 7. By what percent above the particle A, particle B is formed?

Correct Answer: (d) 12%
Solution:

Let the particle A is formed at the rate of x% per microsecond and the particle B is formed at the rate of y% per microsecond
Let when T = 0, then number of A particle = 4 then the number of B particle = 5
When T = 1, (x% of 4)/(y% of 5) = 5/7
4x/5y = 5/7
28x = 25y
x : y = 25 : 28
Therefore, let the particle A is formed at the rate of 25x% per microsecond then the particle B is formed at the rate of 28x% per microsecond
The reqd. % = ((28x − 25x)/25x) ×100 = 300/25
= 12%