BANK & INSURANCE (PERCENTAGE) PART 2

Total Questions: 60

51. 15 % of monthly salary of P is equal to 30 % of monthly salary of Q and 20 % of monthly salary of Q is equal to 30 % of monthly salary of R. If R's monthly income is Rs. 40000, then the total income of P, Q and R is?

Correct Answer: (d) Rs. 220000 
Solution:15P/100 = 30Q/100 → 1
20Q/100 = 30R/100 → 2
From 1, P = 2Q
From 2, 2Q = 3R (Here, R = 40000)
Q = (3×40000)/2 = 60000
P = 2Q = 2×60000 = 120000
P + Q + R = 120000 + 60000 + 40000
= 220000
The total income of P, Q and R is Rs. 220000

52. In company A, 40% of the total employees are male and 80% of the female employees working in IT department. Out of 60% of the total employees are working in IT department. If the total employee in company A is 3200, then find the number of male employees from IT department?

Correct Answer: (a) 384 
Solution:

Total male = 40/100 × 3200 = 1280
Total female = 60/100 × 3200 = 1920
Total number of employees from IT department = 60/100 × 3200 = 1920
Number of female employees from IT department = 1920 × 80/100 = 1536
Number of male employees from IT department = 1920 − 1536 = 384

53. 20% of the voters did not cast their vote in an election between two candidates. 10% of the votes polled were found invalid. The successful candidate got 56% of the valid votes and won by a majority of 1728 votes. The number of voters enrolled on the voters list was?

Correct Answer: (d) 20000 
Solution:

The successful candidate got 56% of the valid votes and won by a majority of 1728 votes.
(56% - 44%) of votes = 1728
12 % of votes = 1728
According to the question,
20 % voters didn’t cast their votes and 10 % of the votes are invalid. So,
= > (80/100)×(90/100)× total voters
= 1728×(100/12)
= > Total voters
= (1728×10×100) / (8×9×12)
= 20000

54. In a class, out of 40% of the students are boys. 75% of the girls are passed in the examination. If the total number of students in the class is 60 and the out of 70% of the students are passed the examination in the class, find the total number of boys passed in the class?

Correct Answer: (b) 15
Solution:

Total boys in the class = 60 × 40/100 = 24
Total girls in the class = 60 × 60/100 = 36
Number of girls passed the examination
= 36 × 75/100 = 27
Total number of students passed the examination
= 60 × 70/100 = 42
Number of boys passed the examination
= 42 - 27 = 15

55. A certain number of employees in the company, which has two departments IT and HR. 70% of the IT department employees are 50 more than that of the 60% of the HR department employees. 80% of the HR department employees is 80 more than 40% of the IT department employee. What is the number of IT department employees in the company?

Correct Answer: (a) 275 
Solution:

Total number of employees = x
Number of IT department employees = y
Number of HR department employee = (x - y)
70/100 × y = 60/100 × (x - y) + 50
70y = 60x - 60y + 5000
60x - 130y + 5000 = 0 …(1)
80/100 × (x - y) = 40/100 × (y) + 80
80x - 80y = 40y + 8000
80x - 120y - 8000 = 0 …(2)
(1) × 4 - (2) × 3
-160y = -44000
y = 275

56. A fruit seller had some oranges and apples. He sold 20% oranges to A, 40% of remaining to B and had 48 oranges left. Similarly, he sold 40% apples to A, 100 apples to B and had 10% apples left. Find the total number of apples and oranges that the shopkeeper had initially.

Correct Answer: (c) 300
Solution:

Let ‘a’ and ‘b’ are number of oranges and apples respectively.
Oranges sold to A = 20/100 × a = 0.2 a
Oranges sold to B = (a − 0.2a) × 40/100 = 0.32 a
Remaining number of oranges = a − (0.2a + 0.32 a)
= 0.48 a

⇒ 48 = 0.48 a
⇒ 100 = a

Apples sold to A = 40/100 × b = 0.4 b
Remaining number of Apples = 10/100 × b = 0.1 b
Apples sold to B = 1 b
⇒ 100 = b − (0.4 b + 0.1 b)
⇒ 100 = 0.5 b
⇒ 200 = b
Total number of apples and oranges = a + b = 100 + 200 = 300

Or

Short cut:
Let ‘a’ and ‘b’ are number of oranges and apples respectively.
48 = 60% of (100 − 20)% of a
a = 100
100 = (100 − 40 − 10)% of b
b = 200
Total apples and oranges = 100 + 200 = 300

57. In class of 80 students and 5 teachers, each student got sweets that are 15% of the total number of students and each teacher got sweets that are 20% of the total number of students. How many sweets were there?

Correct Answer: (c) 1040
Solution:Total number of sweets
= 80×(15% of 80) + 5×(20% of 80)
= 80×12 + 5×16 = 1040

58. The value of the machine depreciated every year by 13%. If the value of the machine is 260000, find the value of the machine after 2 years.

Correct Answer: (d) 196794 
Solution:Value of the machine = 260000 × 87/100 × 87/100
= 196794

59. The total income of Saara and Vinay is Rs. 55000. If the income of Saara and Vinay is increased by 15% and 12% respectively, then the total income of both of them is increased by Rs. 7200. Find the income of Saara?

Correct Answer: (a) Rs. 20000 
Solution:Let the income of Saara and Vinay be x and y respectively.
x + y = 55000 → (1)
15% of x + 12 % of y = 7200
15x + 12y = 720000 → (2)
By solving the equation (1) and (2), we get,
x = 20000, y = 35000
The income of Saara = Rs. 20000

60. Manvi spends 15 % of her monthly salary on food. 20 % on housing rent and 13 % on her children's education. Of the remaining salary, she spends 30 % on groceries and 15 % on other expenses. Now she is left with Rs. 8580. Find her annual salary.

Correct Answer: (b) Rs. 360000
Solution:Let Manvi’s monthly salary be X,
X × (52/100) × (55/100) = 8580
X = 8580 × (100/52) × (100/55)
X = Rs. 30000
Manvi’s annual salary = 30000 × 12 = Rs. 360000