BANK & INSURANCE (PERCENTAGE) PART 3

Total Questions: 60

31. Find the ratio of messages received by Ramesh in whatsapp to the messages received by Raju in facebook. If the total messages received by Ramesh in whatsapp and facebook are 160% of messages received by Raju in facebook.

Correct Answer: (b) 224: 365 
Solution:According to question,
Total messages received by Ramesh in whatsapp and facebook = 160/100 × 1460 = 2336
So, messages received by Ramesh in whatsapp
= 2336 - 1440 = 896
Now, required ratio = 896 : 1460 = 224 : 365

32. Rajeev spent 15 % of his monthly salary on food, 20 % on children's education, 10 % on insurance and X % on other expenses. If the difference between the amount spent on food and insurance is Rs. 4000 and the saving is Rs. 20000, then find the value of X?

Correct Answer: (d) 30 
Solution:

According to the question,
(15% - 10%) of salary = 4000
5% of salary = 4000
Total salary = 4000 × (100/5) = Rs. 80000 = 100%
Savings % = (20000/80000) × 100 = 25%
Total salary (100%) = Expense (75%) + Savings (25%)
75% = (15% + 20% + 10% + X%)
X% = 75% - 45% = 30%

33. Raghav spent 20% of his monthly income on household, 10% of the rest on education, 25% of the rest on entertainment and 20% of the rest on other expenditures. He saves Rs.__. Amount spent by Raghav on entertainment is Rs._. Which of the following option/options satisfy the given condition?

Correct Answer: (d) All of these
Solution:

Let, total income of Raghav be Rs. P

(a)
(100 - 20)/100 × (100 - 10)/100 × (100 - 25)/100 × (100 - 20)/100 × P = 10800
=> 80/100 × 90/100 × 75/100 × 80/100 × P = 10800
=> P = 10800 × 100/80 × 100/90 × 100/75 × 100/80
=> P = Rs. 25000
Amount spent by Raghav on entertainment
= 80/100 × 90/100 × 25/100 × 25000
= Rs. 4500 = 4500
=> Satisfies the given condition.

(b)
(100 - 20)/100 × (100 - 10)/100 × (100 - 25)/100 × (100 - 20)/100 × P = 13500
=> 80/100 × 90/100 × 75/100 × 80/100 × P = 13500
=> P = 13500 × 100/80 × 100/90 × 100/75 × 100/80
=> P = Rs. 31250
Amount spent by Raghav on entertainment
= 80/100 × 90/100 × 25/100 × 31250
= Rs. 5625 = 5625
=> Satisfies the given condition.

(c)
(100 - 20)/100 × (100 - 10)/100 × (100 - 25)/100 × (100 - 20)/100 × P = 18900
=> 80/100 × 90/100 × 75/100 × 80/100 × P = 18900
=> P = 18900 × 100/80 × 100/90 × 100/75 × 100/80
=> P = Rs. 43750
Amount spent by Raghav on entertainment
= 80/100 × 90/100 × 25/100 × 43750
= Rs. 7875 = 7875
=> Satisfies the given condition.

34. The bag contains a certain number of red, yellow, orange and blue balls. The number of red balls is equal to 120% of the number of blue balls and the number of yellow balls is 50% of the number of red balls. If 40% of the orange balls is equal to the 60% of the blue balls and difference between the number of orange and red balls is 15, the find the total number of balls.

Correct Answer: (c) 215 
Solution:

Let Blue balls = x
Red balls = x × 120/100 = 6x/5
x × 60/100 = 40/100 × Orange balls
Orange balls = 3x/2
Yellow balls = 3x/5
3x/2 - 6x/5 = 15

15x - 12x = 150
x = 50
Total number of balls = x + 6x/5 + 3x/2 + 3x/5
= 50 + 60 + 75 + 30 = 215

35. Total number of Red and Blue balls in a box is 100. If certain number of red and blue balls added to the box, then the number of red balls is increased by 20% and the number of blue balls increased by 9 and then total number of balls in the box is increased by 23%. What is the ratio of the initial number of red to blue balls in the box?

Correct Answer: (e) None of these
Solution:

Number of red balls = x
Number of blue balls = 100 - x
x × 120/100 + (100 - x + 9) = 100 × 123/100
6x/5 + 109 - x = 123
6x + 545 - 5x = 123 × 5
x = 70
Number of blue balls = 100 - 70 = 30
Required ratio = 7 : 3

36. Rajeev scored 412 marks in an exam and Sanjay got 75 % marks in the same exam which is 8 marks more than Rajeev. If the minimum passing marks in the exam is 35 %, then how much more marks did Rajeev score than the minimum passing marks?

Correct Answer: (c) 216
Solution:

Let x be the total mark in that exam, then
Rajeev’s score = 412 marks, Sanjay’s score
= 75% = Rajeev’s score + 8
Sanjay = 412 + 8 = 420 = 75% of total marks
(75/100) × x = 420
x = 420 × (100/75) = 560
Minimum passing marks = 35% of total marks
=> (35/100) × 560 = 196
Rajeev scored 216 marks more than the passing marks.

37. If Renu has one laptop worth of Rs.18000, 2 mobiles worth of Rs.30000 and one car worth of Rs.4 lakh. In next year, the cost of car decreased by 20%, price of laptop is increased by 10% and the cost of mobiles is decreased by 5%, then what is the percentage change in the net worth of Renu?

Correct Answer: (d) 17.8% decreases
Solution:

Total costs of all the properties
= 18000 + 30000 + 40000 = 448000
New worth of the Renu properties
= ((18000 × 110/100) + (30000 × 95/100) + (40000 × 80/100))
= 19800 + 28500 + 320000
= 368300
Required percentage
= (448000 - 368300)/448000 × 100
= 17.8% decreases

38. The number of employees in company A is 20% more than the number of employees in company B and the number of employees in C is 30% more than the number of employees in A. If the ratio of the number of male to female in A, B and C is 13: 12, 11: 9 and 3: 2 respectively, then the total number of female employees in all the companies together is approximately what percent of the total number of employees in all the companies together?

Correct Answer: (a) 44% 
Solution:

Number of employees in B = x
Number of employees in A = x × 120/100 = 6x/5
Number of employees in C = 6x/5 × 130/100
= 39x/25
Female in A = 6x/5 × 12/25 = 72x/125
Female in B = 9/20 × x = 9x/20
Female in C = 39x/25 × 2/5 = 78x/125
Required percentage
= (72x/125 + 9x/20 + 78x/125)/(x + 6x/5 + 39x/25) × 100
= (288x + 225x + 312x)/500 × 25/(25x + 30x + 39x) × 100
= 44%

39. The number of students from class A is 50% more than the number of students from class B and the number of students from C is 60% more than the number of students from D. If the number of students from D is 40 less than the number of students from B and the average number of students from C and A is 123, then find the total number of students from all the class together?

Correct Answer: (e) 406
Solution:

Number of students from B = x
Number of students from A = x × 150/100 = 3x/2
Number of students from D = y
Number of students from C = y × 160/100 = 8y/5
x - y = 40 ...(1)
3x/2 + 8y/5 = 123 × 2 = 246 ...(2)
(2) - (1) × 15
31y = 2460 - 600
y = 60
x = 40 + 60 = 100

Number of students from A = 150/100 × 100 = 150
Number of students from C = 60 × 160/100 = 96
Required total = (96 + 150 + 100 + 60) = 406

40. There are three sections I, II and III in a college. Ratio of the total number of students in section I, II and III is 4 : 5 : 7. In section III, the ratio of number of boys to girls is 13 : 12. In section I, 40% of total students is boys. In section II, number of boys is 66.66% less than the number of girls of section II. Find total number of boys is what percentage more or less than the total number of girls in all the section together? (Approximately)

Correct Answer: (c) 32% less
Solution:Let number of students in section I, II and III be 400x, 500x and 700x respectively.
So,
Boys in section III = 700x × 13/25 = 364x
Girls in section III = 700 × 12/25 = 336x
In section I, number of boys = 400x × 40/100 = 160x
So, the number of girls is = 400x – 160x = 240x
Let number of girls in section II = x
So, according to the question,
x/3 + x = 500x
= 4x/3 = 500x
⇒ x = 375x
So, number of boys in section II
= 500x – 375x = 125x
And the total number of girls in all sections
= 336x + 240x + 375x = 951x
So, the required percentage
= (951x – 649x)/951x × 100
= 302x/951x × 100 ≈ 32% less