Solution:Let, Cost price of vehicle be X uday
⇒ Selling price of vehicle at uday
= X + ((15/100) × X)
⇒ Selling price of vehicle at uday = C.P for prabhakar = (23/20) × X
⇒ Selling price for prabhakar = ((23/20) × X) + ((23/20) × X × (10/100))
⇒ Selling price for prabhakar = Cost price for lavi
= (23/20) × (11/10) × X
⇒ Selling price for lavi = cost price for Deepak = (23 × 11)/(20 × 10) × X × (1.125)
⇒ Selling price for lavi = Cost price for Deepak =
(23/20) × (11/10) × (9/8) × X
⇒ Selling price for Deepak = cost price for baarish =
(23 × 11 × 9)/(20 × 10 × 8) × X (1 – 0.20)
⇒ Cost price for baarish = ((23 × 11 × 9 × 4)/(20 × 10 × 8 × 5)) × X
⇒ C.P for baarish = (9108/8000) × X
⇒ Difference = (9108/8000) × X – X
⇒ Difference = (1108/8000) × X
∴ Required difference (1108/8000) × X