BANK & INSURANCE (RATIO AND PROPORTION) PART 2

Total Questions: 70

41. The ratio of the number of students studying in school A, B and C is 5 : 8 : 4, respectively. If the number of students studying in each of the school is increased by 20%, 25% and 30% respectively, what will be the new respective ratio of the students in schools A, B and C?

Correct Answer: (c) 15:25:13
Solution:

The ratio of the number of students studying in school A, B and C is 5 : 8 : 4, respectively.

New value according to the question,

5 × 120/100 : 8 × 125/100 : 4 × 130/100

⇒ 60 : 100 : 52 = 15 : 25 : 13

42. Rs. 360 is contained in a box. The box has 1 rs, 50 paise and 25 paise coins in the ratio of 2:3:4. Find the total number of 25 paise and 50 paise coins.

Correct Answer: (c) 560
Solution:

Total amount = 360

Ratio ⇒ 2 : 3 : 4

2x, 3x, 4x

⇒ 2x × 1 + 3x × (50/100) + 4x × (25/100) = 360

⇒ 200x + 150x + 100x = 36000

⇒ 450x = 36000

⇒ x = 80

The no of 25 paise and 50 paise coins are,

3x + 4x = 7x = 560

43. 20 boys and 25 girls form a group of social workers. During their membership drive, the same number of boys and girls joined the group (e.g. If 7 boys joined,7 girls joined). How many members does the group have now, if the ratio of boys to girls is 7:8?

Correct Answer: (a) 75
Solution:

Let x boys and x girls joined the group.

According to the question,

(20 + x) / (25 + x) = 7 / 8

⇒ 160 + 8x = 175 + 7x

⇒ x = 15

Total number of the members in the group

= 25 + 20 + 30 = 75

44. A plot has to be divided among A, B and C in the ratio 2 : 3 : 5 respectively. If the area of plot received by C is 6000 m² more than the area of plot received by B, then find the total area of plot received by A and B.

Correct Answer: (a) 15000 m²
Solution:

Let the area of plot received by A, B and C be 2x, 3x and 5x respectively.

As per statement,

3x + 6000 = 5x

On simplification,

x = 3000

Area of plot received by A and B together,

= 2x + 3x = 5x

= 5 × 3000 = 15000 m²

45. The sides of a rectangle are in the ratio 2: 3 and its area is 486sq.m. Find the perimeter of the rectangle.

Correct Answer: (b) 90 m
Solution:

Let 2x and 3x be the sides of the rectangle

We know that, area of rectangle = l × b

2x × 3x = 486

6x² = 486

x² = 81

x = 9

Therefore, length = 2x = 2 × 9 = 18 m

Breadth = 3x = 3 × 9 = 27 m

Therefore, perimeter of the rectangle = 2 (l + b)

= 2 (18 + 27) = 90 m

46. The cost of diamond varies directly as the square of its weight. A diamond broke into four pieces with weights in the ratio 1 : 2 : 3 : 4. if the loss in the total value of the diamond was Rs. 70,000. The price of the original diamond was?

Correct Answer: (a) Rs. 100000
Solution:

Let the weight of the pieces of diamond be x, 2x, 3x, 4x

Total weight of diamond = x + 2x + 3x + 4x = 10x.

Price ∝ (weight)²

⇒ Price = k(weight)² ; Where K is constant

Original price = k(10x)²

Price of pieces = (kx² + 4kx² + 9kx² + 16kx²)

= 30kx²

Loss in price = 100kx² − 30kx²

= 70kx²

which is given as 70,000.

70kx² = 70000

⇒ kx² = 1000

Original price = 100kx²

= 100 × 1000 = 100000

47. A sum of money is divided among A, B, C and D in the ratio of 3:4:9:10 respectively. If the share of C’s is Rs. 2850 more than the share of B, then what is the total amount of money of A and D together?

Correct Answer: (e) None of these
Solution:

Ratio of A, B, C and D is 3 : 4 : 9 : 10 respectively,

According to the question,

C = 2850 + 4x

⇒ 9x = 2850 + 4x

⇒ 5x = 2850

⇒ x = 570

⇒ Total amount of A and D together

= 3x + 10x = 13x = 13 × 570

= Rs. 7410

48. A bag contains Rs.1, 50 paise and 25 paise coins in the ratio of 4 : 3 : 2. If the total value is Rs.30, how many 25 paise coins are present in the bag?

Correct Answer: (b) 10 coins
Solution:

Let number of Rs.1 coins = 4x

And number of 50 paise coins = 3x

And number of 25 paise coins = 2x

Therefore, total value of the coins = 1 × 4x + 0.5 × 3x + 0.25 × 2x

Therefore, 30 = 4x + 1.5x + 0.5x = 6x

⇒ x = 5

Hence, Number of 25 paise coins present in the bag

= 2x

= 2 × 5 = 10 coins

49. A, B and C are partners of a company. During a particular year A received one-third of the profit. B received one-fourth of a profit and C received the remaining Rs.5000. How much did A receive?

Correct Answer: (b) Rs.4000
Solution:

Let the total profit = Rs. A

Therefore, A’s share = A/3

B’s share = A/4

Therefore, C’s share = A − A/3 − A/4

5000 = A − 7A/12 = 5A/12

⇒ A = 12000

Hence, A’s share = A/3 = 12000 / 3 = Rs.4000

50. Niki & Sonu started a business with initial investment of Rs 1300 and Rs 1500 respectively. After 5 months, Niki added Rs 200. After 4 months, Sonu added Rs 500 and after another 3 months, Sonu added Rs 1000. If at the end of the year, they earned the profit of Rs 35200. Calculate Niki's share of profit.

Correct Answer: (b) 13600
Solution:

Niki : Sonu = 1300×5 + 1500×7 : 1500×4 + 2000×3 + 3000×5

= 17000 : 27000 = 17 : 27

Niki’s share = 17×35200 / 44 = 13600