BANK & INSURANCE (RATIO AND PROPORTION) PART 2

Total Questions: 70

51. A man spends Rs.1810 for buying bed sheets at Rs.200 each and pillows at Rs.70 each. What will be the ratio of bed sheets to pillows when maximum numbers of bed sheets are bought?

Correct Answer: (b) 8:3
Solution:

The man can’t purchase more than 8 bedsheets

So cost of 8 bedsheets = 8 × 200 = 1600

Remaining amount = 1810 − 1600 = 210

And in Rs.210 the man can purchase 210/70

= 3 pillows

Required ratio = 8 : 3

52. An amount of money is to be divided among P, Q and R in the ratio of 3:5:7 respectively. If the amount received by R is Rs.4000 more than the amount received by Q, what will be the total amount received by P and Q together?

Correct Answer: (c) Rs.16000
Solution:

52. (c): Difference of amount received by R and Q

= 7 − 5 = 2

Total amount received by P and Q = 3 + 5 = 8

And 2 = Rs.4000

Hence 8 = 4000/2 × 8 = Rs.16000

53. If x runs are scored by A, y runs by B and z runs by C, then x : y = y : z = 3 : 2. If total number of runs scored by A, B and C is 342, the runs scored by each would be respectively

Correct Answer: (b) 162, 108, 72
Solution:

x : y = 3 : 2 = 9 : 6

y : z = 3 : 2 = 6 : 4

∴ x : y : z = 9 : 6 : 4

9a + 6a + 4a = 342

19a = 342

a = 342 / 19 = 18

A = 18 × 9 = 162

B = 18 × 6 = 108

C = 18 × 4 = 72

54. Deepak, Deepika, Dheeraj enter into a partnership with share in the ratio 7/2:4/3:6/5. After 4 months, Deepak increases his share by 50%. If the total profit at the end of one year be 43200, then Dheeraj's share in the profit is ?

Correct Answer: (c) 7200
Solution:

Given ratio = 7/2 : 4/3 : 6/5 = 105 : 40 : 36

Ratio of investments (i.e. ratio of profit)

[105×4 + (150% of 105) × 8] : (40 × 12) : (36 × 12)

= 1680 : 480 : 432

= 35 : 10 : 9

⇒ Dheeraj’s share in the profit = 9/(35+10+9) × 43200 = 7200

55. Equal quantities of three mixtures of milk and water are mixed in the ratio of 1:2, 2:3 and 3:4. The ratio of water and milk in the mixture is?

Correct Answer: (a) 193:122
Solution:

Proportion of milk in the mixture = A : B : C = 1/3 : 2/5 : 3/7

35/105 : 42/105 : 45/105

Quantity of milk in new mixture = 35 + 42 + 45

= 122 litre

Quantity of water in new mixture = (105 × 3) − 122

= 193 litre

Therefore, the ratio of water is to milk = 193 : 122

56. A box has 1 rupee, 50 paisa and 25 paisa coin in the ratio 3:2:5 worth Rs.252. The number of 25 paisa coins in the box is?

Correct Answer: (c) 240
Solution:

Let the ratio of coins be 3x : 2x : 5x.

Then at x = 1

Rupee Rs.1 50p 25p

Coins 3 2 5

Sum 3 1 1.25

Rs. 5.25 × 48 = 252

So, 25 paisa coins, 5 × 48 = 240

57. An outgoing batch of students wants to gift books worth Rs 4,200 to their teachers. If the boys offer to pay 50% more than the girls and an external sponsor gives three times the boy's contribution, then how much should the boys donate?

Correct Answer: (c) Rs 900
Solution:

The ratio of the share girls : boys : sponsors = 1 : 1.5 : 4.5

So the proportion to boy’s share = 1.5/7

Hence, the boys would donate

= 1.5/7 × 4200 = Rs 900

58. In a cricket match there are three types of tickets A, B and C each costing Rs.1000, Rs.500 and Rs.200 respectively. The ratio of ticket sold of category A, B and C is 3 : 2 : 5. If the total collection from selling the tickets is Rs.2.5 crore. Find the total number of tickets sold?

Correct Answer: (c) 50000
Solution:

Number A : B : C = 3 : 2 : 5

Let A = 3x, B = 2x, C = 5x

Then (1000 × 3x) + (500 × 2x) + (200 × 5x) = 25000000

5000x = 25000000

X = 5000

Total tickets = 3x + 2x + 5x = 10x

= 10 × 5000 = 50000

59. 180 sweets are divided among friends A, B, C and D in which B and C are brothers also such that sweets divided between A and B are in the ratio 2 : 3, between A and C in the ratio 2 : 5 and between C and D in ratio 3 : 4. What is the number of sweets received by the brothers together?

Correct Answer: (b) 84
Solution:

A/B = N1/D1, B/C = N2/D2, C/D = N3/D3

A : B : C : D = N1×N2×N3 : D1×N2×N3 : D1×D2×N3 : D1×D2×D3

A/B = 2/3, B/C = 2/5, C/D = 3/4

A : B : C : D

2×2×3 : 3×2×3 : 3×5×3 : 3×5×4

4 : 6 : 15 : 20

B and C together = [(6+15)/(4+6+15+20)] × 180

= 84

60. A bag contains Rs.102 in the form of 1 rupees, 50 paise and 10 paise coins in the ratio 3 : 4 : 10. The number of 10 paise coins is?

Correct Answer: (d) 170
Solution:

Ratio of the number of coins of 1 rupee : 50 paisa : 10 paisa = 3 : 4 : 10

Ratio of total values of coins of 1 rupee : 50 paisa : 10 paisa

= (100 × 3) : (50 × 4) : (10 × 10)

= 300 : 200 : 100 = 3 : 2 : 1

Total value of 10 paisa coins is Rs. 102

= [1 / (3 + 2 + 1)] × Rs. 102 = Rs. 102 / 6

= Rs. 17 = 1700 paisa

No. of 10 paisa coins = 1700 / 10 = 170