Solution:Let initial weight of C = ‘x’ kg
So, initial weight of B = (x − 15) kg
And initial weight of A = x − 15 + 6 = (x − 9) kg
From the question:
[(x − 9) + m] / [x − (m + 9)] = 6/5
5x − 45 + 5m = 6x − 6m − 54
x − 11m = 9 ............(1)
And,
[(x − 15) + (m − 2)] / [x − (m + 9)] = 16/15
15x + 15m − 255 = 16x − 16m − 144
31m − x = 111 ............(2)
From equations (1) and (2):
20m = 120
m = 6, x = 75
Initial weight of A = 75 − 9 = 66 kg
Initial weight of B = 75 − 15 = 60 kg
Required ratio = 66 : 60 = 11 : 10