BANK & INSURANCE (SPEED TIME AND DISTANCE) PART 1

Total Questions: 45

41. Rani started walking to the station half a km from her home at 1 kmph to catch the train in time. After 6 minutes she realized that she had forgotten her purse at home and returned with increased, but constant speed to get it and succeeded in catching the train. Find her latter speed in kmph.

Correct Answer: (a) 1.5 kmph 
Solution:

Distance covered in 6 minute = 6×(1000/60) = 100
She has to cover (500+100) meters in 24 minutes

Required speed = (600/1000)/(24/60) = 1.5 kmph

42. 3/2 of speed = 2/3 of original time 2/3 of original time = original time - 40 minutes 1/3rd of original time = 40 minutes; Thus, original time = 40×3 = 120 minutes = 2 hours

Correct Answer: (e) 2 hours
Solution:

3/2 of speed = 2/3 of original time
2/3 of original time = original time - 40 minutes
1/3rd of original time = 40 minutes;
Thus, original time = 40×3 = 120 minutes = 2 hours

43. A starts from a place at 11 am and travels at a speed of 4kmph, B starts at 1 pm and travels with a speed of 1kmph for 1st hour, 2kmph for next 1 hour and so on. At what time B catch up with A?

Correct Answer: (b) 9.48pm 
Solution:A => 1h = 4km……10h = 40km
B => 1+2+3+4+5+6+7+8 = 36km
They will meet b/w 9 - 10 pm
Relative Speed = 9 - 4 = 5 km/h
B catch up with A = (40-36)×60 / 5
= 9 + 48 min = 9:48pm

44. The distance between 2 stations are 800km. One train starts at 5am from A with 62kmph. Another train starts at 7am from B at 50kmph. When they will meet?

Correct Answer: (c) 1.03pm
Solution:7 - 5 = 2h diff
2×62 = 124
Remaining distance to cover by train from A
= 800 - 124 = 676
62+50 = 676/t
T = 676/112 = 6.03 = 7 + 6.03 = 1.03pm

45. Two trains 180 metres and 120 metres in length are running towards each other on parallel tracks, one at the rate 65 km/hr and other at 55 km/hr. In how many seconds will they be clear of each other from the moment they meet?

Correct Answer: (b) 9 
Solution:

Required time = Sum of the lengths of trains / Relative speed
Relative speed = 65 + 55 = 120 kmph
= 120 × (5/18) m/sec
Required time = (180 + 120) / [(120 × 5)/18]
= (300×18)/(120×5)
= 9 seconds