Solution:
Let the sides of equilateral triangle are 60 km.
Speed of A = 30 km/h
Speed of B = 20 km/h
When, they move in same direction.
Then, difference of speed = 30 - 20 = 10 km/h
So, A will cover the difference of distance (60 km) in 6 hrs
∴ In 6 hrs B will be on point A.
Hence, they meet each other for first time at point 'A'.