Solution:(A & B) can finish the job = 20 days(B & C) can finish the job = 30 days
(A & C) can finish the job = 24 days
Let total work is 120 units (LCM of 20, 30 and 24)
Then, efficiency of A & B = 120/20 = 6 unit/day
120 = 6 unit/day 120/30 = 4 unit/day
Efficiency of A & C = 120/24 = 5 unit/day.
∴ Efficiency of (A, B and C) together per day
= (6+4+5)/2 = 15/2 unit/day
∴ Efficiency of A
= Efficiency of (A + B + C) - Efficiency of (B+C)
= 15/2Â - 4 = 7/2 unit/day
So, A alone finish the job
= (120/7/2) = 240/7 = 34 2/7 days.