Solution:∴ a, b and c are three distinct natural numbers such that a + b + c = abc.Leta a = 1, b = 2, c = 3
1 + 2 + 3 = 1 × 2 × 3
6 = 6
1. The arithmetic mean of a, b and c is = (a+b+c)/3
⇒ (1+2+3)/3 ⇒ 6/3 = 2
'2' is a natural number.
2. The harmonic mean of a, b and c is ⇒ [(1+1+1) ÷ (1/a + 1/b + 1/c)]
⇒ (3abc) ÷ (bc+ab+ac) ⇒ (3×1×2×3) ÷ (6+3+2 )
⇒ 18 / 11 ; 1 < 18 / 11 > 2
Both the statements are correct.