Solution:1. Initial speed = 100m/s2. Total time of flight = 20 s (so the ball takes 10 seconds to reach the top and 10 seconds to come back).
3. Acceleration due to gravity (g) = 10m / (s²)
4. The ball loses 70% of its speed after hitting the ground, so its new speed after the bounce is 30% of 100 m/s, i.e., 30 m/s.
Where: v = 0
u = 30m/s (initial speed after the bounce)
g = 10m/(s²)
h is the height
Now, we can calculate the height the ball will reach after the bounce using the formula:
V² = U² - 2gh
U² + (- V²) / 2g = h
Therefore, the ball will bounce up to a height of 45 meters.