Solution:In the equation, SO₂ + H₂S → 3S + 2H₂O, when we count the number of each atom in the reactant side, we find H = 2, S = 2, O = 2.
• When we count the number of each atom in the product side, we find H = 4, S = 3, O = 2.
• We can then balance the number of each atom in the equation by multiplying reactant and product side with numerical values.
• If we multiply H₂S by 2 in the reactant side, the number of atoms in the product and reactant side gets the balance.