Data Interpretation (UPSC)

Let the number of professors in the university = x According to question

2% of x = 10 ⇒ x = 10 × 100/2 = 500

From the given options, in 1996, the graphs of A & B intersect, which shows, same average profit.

Ans - 1996

From the graph, we observe that the difference between points A & B is more than half of 1000, but less than 1000.

500 <|Difference between A and B |<1000. From the option, + 600 satisfies this condition.

In 2000, Profit of A = 6000

In 1999, profit of A = 4000

Difference = ₹2000

Non-decreasing

For A Agg marks = 60 + 70 + 50 + 30 = 210

Agg max marks = 100 + 100 + 100 + 50 = 350

% Agg marks of A = 210/350 * 100 = 60%

Agg marks 80 + 70 + 60 + 15 = 225

Agg max marks = 150 + 100 + 100 + 25 = 375

% Agg marks of B = 225/375 * 100 = 60%

Difference in agg percentage = 0

Difference in agg percentage is same as difference in mean agg percentage.

Rule out options:-

Option (a): - We clearly see that from 1993 to 94, increase in

pop is less than 5% * (1/21 * 100 < 5)

Option (b): from year 1994 to 1995

Increase in income = (1345-1225)/1225 × 100

= 120/49 * 4 = 480/49 < 10

Not true (c) : per capita income (p.c.i.)

Total Income in an year/Total population in that year.

In 1992 p.c.i= I01000 20 = 5050 > 5000

In 1993 p.c. i = 111100/21 > 5000

In 1994 p.c. i = 122500/22 > 5000

ln 1995 p.c. i = 134500/23 > 5000

Option (c) is correct.

The product of price (in /litre) and the monthly consumption (in litres) in constraint is equal to 2400.

Expected consumption when the price goes up to 80 per litre = 2400/8 = 30 litres

From given years 2000 to 2007

Earnings of A > Earnings of B

So,

Average of A > Average of B

Hence, It can be conducted that the average A earned more than B during this period.

From the graph commodity price are between 10 and 20.