Geometry (Railway Maths) (Part – VI)Total Questions: 501. Two adjacent angles form an angle of 100°. The larger angle is 20° less than five times the smaller angle. The larger angle is: [RRB NTPC 11/02/2021 (Morning) ](a) 90°(b) 75°(c) 80°(d) 70°Correct Answer: (c) 80°Solution:Let the smaller angle = x Larger angle = 5x - 20 A/Q, x + 5x - 20 = 100° ⇒ 6x = 120° ⇒ x = 20° Larger angle = 5 × 20 - 20 = 80°2. When an arm of an angle is extended to double its length then the measure of the angle. [RRB NTPC 11/02/2021 (Morning) ](a) Triples(b) Becomes half(c) Doubles(d) Remains the sameCorrect Answer: (d) Remains the sameSolution:The angle does not change with its arm length.3. What is the sum of all angles of all triangles in the given figure? [RRB NTPC 12/02/2021 (Morning) ](a) 1080⁰(b) 720⁰(c) 360⁰(d) 1440⁰Correct Answer: (d) 1440⁰Solution:Total number of triangle = 8 Sum of the angle in a triangle = 180° Now, the sum of all angles of all triangles = 8 × 180° = 1440°4. In a rhombus ABCD, if <ACB = 40⁰, then <ADB = ? [RRB NTPC 15/02/2021 (Evening) ](a) 70⁰(b) 50⁰(c) 45⁰(d) 60⁰Correct Answer: (b) 50⁰Solution:5. P is the midpoint of side BC of parallelogram ABCD such that <BAP = <DAP If AD = 10cm, then cd = ? [RRB NTPC 15/02/2021 (Evening) ](a) 10 cm(b) 8 cm(c) 5 cm(d) 6 cmCorrect Answer: (c) 5 cmSolution:6. If the difference between the areas of the circumcircle and the incircle of an equilateral triangle is 66 cm², then the area of the triangle is: [RRB NTPC 16/02/2021 (Morning) ](a) 2√3 cm²(b) 10√3 cm²(c) 21√3 cm²(d) 20√3 cm²Correct Answer: (c) 21√3 cm²Solution:7. The ratio of the areas of two triangles is 4 : 3 and the ratio of their heights is 3 : 4. Find the ratio of their bases. [RRB NTPC 16/02/2021 (Evening) ](a) 14 : 9(b) 16 : 3(c) 16 : 9(d) 12 : 7Correct Answer: (c) 16 : 9Solution:8. The base and the altitude of a right-angled triangle are 15 cm and 8 cm respectively. What is the altitude from the opposite vertex to its hypotenuse? [RRB NTPC 16/02/2021 (Evening) ](a)(b)(c)(d)Correct Answer: (c)Solution:9. In a triangle ABC, points D and E are on the sides AB and AC such that DE is parallel to BC and AD / BD = 3 / 5. If AC = 4 cm, Then AE = ? [RRB NTPC 17/02/2021 (Morning)](a) 1.5 cm(b) 1.8 cm(c) 2 cm(d) 2.4 cmCorrect Answer: (a) 1.5 cmSolution:10. If the side of an equilateral triangle is 2 cm, then find the area and the altitude of the triangle. [RRB NTPC 17/02/2021 (Morning)](a) Area = 3/2 cm² and altitude = √3 cm(b) Area = √3 cm² and altitude = √3 cm(c) Area = √3 cm² and altitude = 2/3 cm(d) Area = 2/3 cm² and altitude = √3 cmCorrect Answer: (b) Area = √3 cm² and altitude = √3 cmSolution:Submit Quiz12345Next »