HARYANA AUCTION RECORDER EXAM, 15.05.2016


 

Total Questions: 100

21. 0.863 x 0.637 + 0.863 x 0.363 =?

Correct Answer: (2) 0.863
Solution:? = 0.863*0.637 + 0.863 * 0.363

=0.863 (0.637 + 0.363)

= 0.863 × 1 = 0.863

22. The average speed of a cyclist who covers first, second and third km at 20, 16 and 12 km/ hr respectively (in kmph) is:

Correct Answer: (4) 15.32
Solution:Total distance covered = 3 Km

Time= 1\20+1\16+1\12

=(12+15+20)\240= 47\240 hours

∴ Average speed

= 3\37 = 3*240\47 = 720\47

= 15.32 km\hr

23. The sum of all positive integral multiples of 5 less than 100 is:

Correct Answer: (1) 950
Solution:Required sum

= (5+10+15+ ------+95)

= 5(1+2+3+ -------+19)

= 5 * (19*20\2= 950

⌊∴ 1+2+3+......+n=  n(n+1)\2⌉

24. A piece of work can be done by 6 men and 5 women in 6 days or 3 men and 4 women in 10 days. It can be done by 9 men and 15 women in:

Correct Answer: (3) 3 days
Solution:According to the question 6 x 6 men + 5 x 6 women = 3 x 10 men + 4 x 10 women

⇒ women 36 men + 30 women = 30 men + 40 women

⇒ (36 - 30)  men = (40 - 30) women

⇒ 6 men =10 women

⇒ 3 men = 5 women

∴ 6 men+ 5 women = 10+5 = 15 women

9 men + 15 women = 15 +15 = 30 women

∴M1D1 = M2D2

⇒ 15*6 = 30*D2

⇒D2= (15*6)\30

= 3 days

25. If Sunil rows at the rate of 5 kmph in still water and his rate against the current is 3.5 kmph. then Sunil's rate along the current is.

Correct Answer: (3) 6.5 kmph
Solution:Speed in still water

= 1\2 down speed streem  + upstreem speed

⇒ 5 = 1\2 (x +3.5)

Where  x =  down streem speed

⇒ 10 = x + 3.5

∴  x = 10 - 3.5 = 6.5 km\hr

26. There are two taps to fill a tank while a third to empty it when the third tap is closed, they can fill the tank in 10 min- utes and 12 minutes respec tively. If all the three tapes be opened, the tank is filled in 15 minutes. If the first two taps are closed, in what time can the third tap empty the tank when it is full?

Correct Answer: (3) 8 min and 34 sec
Solution:Let third pipe can empty the bank in x mins. when all the three pipes opened.

1\15= 1\10 + 1\12 - 1\x

⇒ 1\x = 1\10 + 1\12 - 1\15

=( 6+5- 4)\60= 7\60

∴ x= 60\7 minutes

= 8 minutes 4\7*60 second

= 8 minutes 34 second

27. The LCM of two numbers is 2310 and their HCF is 30. If one of the number is 7 x 30, find the other number.

Correct Answer: (2) 330
Solution:I*II = LCM* HCF

⇒ 7*30 * II

= 30 * 2310\7*30 = 330

28. 10 years ago, Chandravati's mother was 4 times older than her daughter. After 10 years, the mother will be twice older then the daughter. The present age of Chandravati is.

Correct Answer: (3) 20 years
Solution:10 years ago

Age of daughter = x year Age of mother = 4x year

10 years later

Age of daughter = (x + 20) age

Age of mother = (4x + 20) age

As per question

4x+20= 2 (x + 20)

⇒4x+20= 2x + 40

⇒4x-2x= 40-20

⇒ 2x=20⇒ x = 10

∴ Present age of Chandravati = x + 10 = 20 year

29. A lent Rs. 600 to B for 2 years and Rs. 150 to C for 4 years and received altogether from both Rs. 90 as simple interest. The rate of interest is.

Correct Answer: (2) 5%
Solution:Rate of Interest = R%

Interest= PRT\100

∴      600*R*2\100 + 150*R*4 \100

=90

⇒12 R + 6 R = 90

⇒18 R = 90

⇒ R= 90\18 = 5% Per year

30. If a: b 2 : 3 and b : c=5 : 7. then a : c = ?

Correct Answer: (1) 10:21
Solution: