HCF and LCM – Railway MathsTotal Questions: 5021. Rajesh has 180 litres of Oil A and 220 litres of Oil B. He fills a number of identical containers with the two types of oil in a manner that each container has only one type of oil, and all containers are completely filled. What can be the maximum volume (in litres) of each container that Rajesh uses, so that all the oil that Rajesh has, of both the types, can be poured into these containers? [Group D 08/09/2022 (Afternoon)](a) 80 (b) 20(c) 40(d) 60Correct Answer: (b) 20Solution:H.C.F of 180 and 220 = 20Hence, The maximum volume of container = 20 litres22. The HCF of (X⁴ – Y⁴), (X⁸ – Y⁸) and (X² – Y²) is: [Group D 08/09/2022 (Evening)](a) (X – Y)(X + Y)(b) (X – Y)(X + Y)(X – Y)(X + Y)(c) (X – Y)(X + Y)(X + Y)(d) (X + Y)(X + Y)Correct Answer: (a) (X – Y)(X + Y)Solution:(x⁴ − y⁴), (x⁸ − y⁸) and (x² − y²)⇒ x⁴ − y⁴ = (x² − y²)(x² + y²)= (x + y)(x − y)(x² + y²)⇒ x⁸ − y⁸ = (x⁴ − y⁴)(x⁴ + y⁴)= (x² − y²)(x² + y²)(x⁴ + y⁴) = (x + y)(x − y)(x² + y²) (x⁴ + y⁴)⇒ x² − y² = (x + y)(x − y)Hence, H.C.F = (x + y)(x − y)23. The highest common factor of any two distinct prime numbers is: [Group D 09/09/2022 (Evening)](a) 3(b) 0(c) 2(d) 1Correct Answer: (d) 1Solution:The highest common factor of any two distinct prime numbers is always 1.24. Which of the following is a pair of co-prime numbers? [Group D 12/09/2022 (Afternoon)](a) 81, 16(b) 363, 77(c) 455, 49(d) 52, 24Correct Answer: (a) 81, 16Solution:A pair of numbers whose HCF is 1 called the pair of co-prime numbersHCF of 81 and 16 = 1therefore, option (a) is the right answer25. The greatest number which divides 1876, 12503 and 6877 leaving 1,3 and 2 respectively is: [Group D 15/09/2022 (Morning)](a) 675(b) 625(c) 555(d) 655Correct Answer: (b) 625Solution:1876 − 1 = 1875,12503 − 3 = 12500 and 6877 − 2 = 6875H.C.F of 1875, 12500 and 6875 = 625Therefore the greatest no. which divides 1876, 12503 and 6877 leaving 1, 3 and 2 respectively is 62526. A farmer plants three different types of plants in equal numbers in a garden. All plants of a type are planted to form a rectangle, in which no rectangle contains more than one type, and no plants of any type are left out. After all the plants were planted, the aisle with Plant A had 70 rows, the rectangle with Plant B had 28 rows, and the rectangle with Plant C had 42 rows. Find the minimum number of plants of each type planted by the farmer in the garden. [Group D 16/09/2022 (Afternoon)](a) 140(b) 210 (c) 420(d) 70Correct Answer: (c) 420Solution:Minimum number of plants of each type = L.C.M of (28, 42, 70) = 42027. Let R be the greatest number which when divides 41, 71 and 91 leaves the same remainder. Find the LCM of R and 45. [Group D 20/09/2022 (Morning)](a) 45(b) 90(c) 75(d) 10Correct Answer: (b) 90Solution:H.C.F of (91 − 71), (71 − 41), (91 − 41)H.C.F of 20, 30, 50 is 10Now, the L.C.M of 10 and 45 = 9028. Consider two numbers whose LCM + HCF = 504, and LCM - HCF = 456. If one of these two numbers is 96, find the other number. [Group D 27/09/2022 (Afternoon)](a) 100(b) 126(c) 120 (d) 130Correct Answer: (c) 120 Solution:LCM + HCF = 504 (i) &LCM − HCF = 456 (ii)Solve eq (i) and eq (ii) we get, LCM = 480 & HCF = 24We know that LCM × HCF = 1st number × 2nd number⇒ 480 × 24 = 96 × 2nd number⇒ 2nd number = 12029. The LCM of fractions is calculated as [Group D 28/09/2022 (Afternoon)](a) 25(b) 30(c) 15 (d) 20Correct Answer: (b) 30Solution:30. Find the ratio between the LCM and the HCF of 5, 15, and 20. [Group D 30/09/2022 (Morning)](a) 14 : 3(b) 8 : 1 (c) 12 : 1(d) 11 : 2Correct Answer: (c) 12 : 1Solution:LCM of 5, 15 and 20 = 60HCF of 5, 15 and 20 = 5Ratio of LCM and HCF = 60 : 5 = 12 : 1Submit Quiz« Previous12345Next »