HCF and LCM – Railway MathsTotal Questions: 5041. Find the HCF of (3⁴⁵ − 1) and (3³⁵ − 1). [NTPC CBT - I 17/01/2021 (Morning)](a) 728 (b) 81 (c) 80 (d) 242Correct Answer: (d) 242Solution:Numbers are (3⁴⁵ − 1) and (3³⁵ − 1) HCF of 45 and 35 = 5HCF of (3⁴⁵ − 1) and (3³⁵ − 1) = 3⁵ − 1 = 243 − 1 = 24242. What is the product of LCM and HCF of 18 and 42? [NTPC CBT - I 18/01/2021 (Evening)](a) 746 (b) 736(c) 756(d) 766Correct Answer: (c) 756Solution:As we know product of any two numbers = product of LCM and HCF of those two numbers;So, the product of LCM and HCF of 18 and 42 = 18 × 42 = 75643. f the HCF of 51 and 85 is expressed in the form of 51m - 85, then the value of m will be: [NTPC CBT - I 20/01/2021 (Morning)](a) 1(b) 5(c) 3 (d) 2Correct Answer: (d) 2Solution:The HCF of 51 and 85 is = 17;So, 51m − 85 = 1751m = 17 + 85 ⇒ m = 244. If P = a × m × r and Q = b × m × 2 × r, where a, b, m, r are odd primes. Then the HCF of P and Q is.. [NTPC CBT - I 21/01/2021 (Evening)](a) a r(b) b r(c) 2 r(d) m rCorrect Answer: (d) m rSolution:ATQ,P = a × m × rQ = b × m × 2 × r (where a, b, m, r are odd primes)Since HCF is common factor presence in all terms,So HCF of P and Q will be mr.45. A number lies between the cubes of 11 and 12. If the number is divisible by twice of 80 and 6 both, what will the number? [NTPC CBT - I 29/01/2021 (Morning)](a) 1350(b) 1560 (c) 1680(d) 1440Correct Answer: (d) 1440Solution:The number is divisible by 160 and 12 both.So the number must be divisible by LCM of 160 and 12.LCM of 160 and 12 = 480The required number should be multiple of 480.480 × 3 = 144046. The LCM of two positive integers is thrice the larger number. The difference of the smaller number and the HCF of two numbers is 6. The smaller number is: [NTPC CBT - I 31/01/2021 (Evening)](a) 9(b) 5(c) 11 (d) 7Correct Answer: (a) 9Solution:Let the smaller number = aAnd bigger number = bA/Q, LCM = 3bAnd a − HCF = 6 ⇒ HCF = a − 6HCF × LCM = Product of two numbers⇒ (a − 6) × 3b = ab⇒ 3a − 18 = a ⇒ 2a = 18 ⇒ a = 947. If a, b, c, d are four numbers, such that the LCM of a and b is b, the LCM of b and c is c and the LCM of c and d is d, then the LCM of a, b, c, and d will be: [NTPC CBT - I 03/02/2021 (Morning)](a) d(b) (a + b + c + d)/4(c) a(d) cCorrect Answer: (a) dSolution:LCM of a and b = bLCM of b and c = cLCM of a, b, c = cLCM of c and d = dSo, LCM of a, b, c, and d = d48. The HCF of two numbers is 19 and the other two factors of their LCM are 11 and 13. The larger of the two numbers is: [NTPC CBT - I 04/02/2021 (Evening)](a) 241 (b) 243 (c) 247(d) 249Correct Answer: (c) 247Solution:Two factors of their LCM are 11 and 13So the numbers will be11 × HCF and 13 × HCFLarger number = 13 × 19 = 24749. If the sum of two numbers is 84 and their HCF and LCM are 3 and 124 respectively, the sum of the reciprocals of the two numbers will be: [NTPC CBT - I 04/02/2021 (Evening)](a) 11/31 (b) 9/31 (c) 8/31 (d) 7/31Correct Answer: (d) 7/31Solution:Let the numbers be x and yA/Q, x + y = 84Product of two numbers = HCF × LCM⇒ xy = 3 × 124 = 372Now,1/x + 1/y = (x + y) / xy = 84 / 372 = 7 / 3150. Three different containers contain a mixture of milk and water, measuring 403 litres, 434 litres and 465 litres, respectively. The biggest measure required to measure all the different quantities exactly is: [NTPC CBT - I 11/02/2021 (Morning)](a) 41 litres(b) 32 litres(c) 31 litres(d) 7 litresCorrect Answer: (c) 31 litresSolution:HCF of (403, 434, 465) = 31The biggest measure required to measure all the different quantities exactly is = 31 litresSubmit Quiz« Previous12345