Solution:The velocity of a particle moving along the x-axis varies according to the expression, = Vₓ = 40 - 5t²We have to find average acceleration in the time interval t = 0 to t = 2s.
We know, rate of change of velocity with respect to time is known as acceleration.
So, a = dVx/dt = dt(40 - 5t²)/dt = - 10t
Now, average acceleration in time interval (t = 0 to t = 2s) = {acceleration at( t = 0) + acceleration at ( t = 2s )}/2 = {-10(0) + (-10)(2)}/ 2 = - 10m/s².
Here negative sign indicates that acceleration is just opposite direction of its motion.