Solution:(B.O)= 1/2 [(Number of electron in anti bonding number) - (Number of electron in bonding number)]For, O₂ :B. O = 1/2 [10 - 6] = 2
For, = O⁻₂ :B. O = 1/2 [10 - 7] = 1.5
For, O⁺2 :B. O = 1/2 [10 - 5] = 2.5
For, = O⁻²2 :B. O = 1/2 [10 - 8] = 2
So, the increasing between of order
O⁻²2 <O⁻₂< O₂<O⁺2