Solution:Efficiency of tank A = 1/20Efficiency of tank B= 1/60
Combined efficiency = 1/20 + 1/60
= 4/60 = 1/15
Work in 10 minutes 1/15 * 10 = 2/3
Empty part = 1 - 2/3 = 1/3
Time required to fill empty part by 2nd pipe
= empty part/efficiency = 1/3 / 1/60= 20