HSSC PATWARI EXAM

Total Questions: 100

91. 1.086 - 0.3983 - 0.669=?

Correct Answer: (1) 0.6208
Solution:1.086-0.3983-0.669

β‡’1.086 - (0.3983 + 0.669)

β‡’1.086 - (0.4652) = 0.6208

92. A library has an average num- ber of 510 visitors on sunday and 240 on other days. The average number of visitors per day in a month of 30 days beginning with sunday is:

Correct Answer: (3) 285
Solution:There will be five Sundays Visitor in 5 Sunday

= 5 Γ—Β  510 = 2550

Visitor on Remaining 25 days

= 25 Γ— 240 = 6000

Average visitors everyday

= (2550 + 6000)/30 = 285

93. The sum of all odd numbers between 100 and 200 is:

Correct Answer: (3) 7500
Solution:Sn = 101 + 103 + 105 +.... + 199

This is Arithmetic Progression

a = 101, d = 2 ,l = tn = 199

a + (n - 1) Γ— d = 199

β‡’ 101 + (n - 1) Γ— 2 = 199

β‡’n = 50

Sn = n/2(a + 1) = 50 2 (101+199)

=50/2(300)

= 25 Γ— 300 = 7500

Required sum = 7500

94. Himanshu does half as much work as Yogesh in three - fourth of the time. if together they take 18 days to complete the work, how much time shall Yogesh take to do it?

Correct Answer: (1) 30 days

95. Two stations a and b are 110 km apart on a straight line. One train starts from a at 7 a.m. And travels towards bat 20 kmph. Another train starts from b at 8 a.m. And travels onwards at a speed of 25 kmph. At what time will they meet?

Correct Answer: (2) 10 Ξ‘.Μ.
Solution:Let both trains meet x hour later than 7 AM

distance covered by A in x hours = 20xkm Distance covered by B in (x- 1) hours.

= 25(x - 1) km

20x + 25(x - 1) = 110

45x = 110 + 25

45x = 135

x = 3

They meet at 10 AM.

96. 25/0.005 = ?

Correct Answer: (2) 5000
Solution:25/0.005 = 25/5 Γ— 1000 = 5000

97. A man covers a distance from town a to town b on scooter at 30 kmph and rides back from b to a at 20 kmph. His average speed is

Correct Answer: (1) 24 kmph
Solution:Average speed = (2xy)/(x + y) = (2 Γ— 30 Γ— 20)/(30 + 20) = 1200/50 = 24km / hr

98. Five numbers in geometric progression are such that their product is 32. Find the third number.

Correct Answer: (3) 2
Solution:Let the numbers are a/(r ^ 3) , a/r, a r ^ 3 then, a/(r ^ 3) Γ— a/r Γ— aΓ—arΓ—a Γ— r ^ 3 = 32

β‡’ a ^ 5 = 32

β‡’ a = 2

Third number a = 2

99. Twelve men can complete a work in 8 days. Three days after they started the work, 3 or more men joined. In how many days will all of them together complete the remaining work?

Correct Answer: (1) 2
Solution:1 day work by 12 men = 1/8

1 day's work by 1 man

= 1/8 Γ— 1/12 = 1/96

3 day work by 12 men

= 1/8Β  Γ— 3 = 3/8

Remaining work = 1 - 3/8 = 5/8

1 day's work by one man= 1/96

1 day's work by 15 men = 1/96 Γ— 15 = 15/96

15/96 work's done in 1 day

5/8 work will be done= 5/8 Γ— 96/15 = 12/3 = 4 days

100. Which of the following fractions is less than 7/8 and greater than 1/3?

Correct Answer: (4) 17/24
Solution:17/24 is smalles than 7/8 & bigger than 1/3