Solution:A takes = 6 dayB B takes = 12 day
Total work (A and B LCM) = 12
Efficiency A = 1212=2\frac{12}{12} = 21212=2
Efficiency B = 126=1\frac{12}{6} = 1612=1
∴ Time by C = 122+1=4\frac{12}{2 + 1} = 42+112=4 days
Efficiency C = 124=3\frac{12}{4} = 3412=3
Time taken by B & C together
= Total workTotal efficiency=124=3\frac{\text{Total work}}{\text{Total efficiency}} = \frac{12}{4} = 3Total efficiencyTotal work=412=3 days