Mathematics (NDA/NA SOLVED PAPER 2022-II) (01 to 50)Total Questions: 5021. If d is the common difference of A, and D is the common difference of B, then which one of the following is always correct?Let P be the sum of first n positive terms of an increasing arithmetic progression A. Let Q be the sum of first n positive terms of another increasing arithmetic progression B. Let P : Q = (5n+4): (9n+6)(a) D > d(b) D < d(c) 7D > 12d(d) None of the aboveCorrect Answer: (c) 7D > 12dSolution:(c)22. What is the value of q if the coefficients of x³ and x⁶ are equal?Consider the binomial expansion of (p + qx)⁹ :(a) p(b) 9p(c) 1/p(d) p²Correct Answer: (a) pSolution:23. What is the ratio of the coefficients of middle terms in the expansion (when expanded in ascending powers of x)?Consider the binomial expansion of (p + qx)⁹ :(a) pq(b) p/q(c) (4p)/(5q)(d) 1/(pq)Correct Answer: (b) p/qSolution:24. Under what condition the coefficients of x² and x⁴ are equal?Consider the binomial expansion of (p + qx)⁹ :(a) p : q = 7 : 2(b) p² : q = 7 : 2(c) p : q = 2 : 7(d) p² : q² = 2 : 7Correct Answer: (b) p² : q = 7 : 2Solution:Coefficient of x² = coefficient of x⁴ ⁹C₂ p⁷ q² = ⁹C₄ p⁵ q⁴ . 9.8/2.1 p² = 9.8.7.6/ 4.3.2.1 q² p²/q² = 7/225. How many 4-letter words each of two vowels and two consonants with or without meaning, can be formed?Consider the word 'QUESTION' :(a) 36(b) 144(c) 576(d) 864Correct Answer: (d) 864Solution:Number of words contains two vowels and two consonants = ⁴C₂ . ⁴C₂ × 4! = 6 . 6 . 24 = 86426. How many 8-letter words with or without meaning, can be formed such that consonants and vowels occupy alternate positions?Consider the word 'QUESTION' :(a) 288(b) 576(c) 1152(d) 2304Correct Answer: (c) 1152Solution:C V C V C V / C V or VC VC VC VC Number of 8 letter words such that vowels and consonants occupy alternate positions. = 2 × 4! 4! = 2 × 24 × 24 = 115227. How many 8-letter words with or without meaning, can be formed so that all consonants are together?Consider the word 'QUESTION' :(a) 5760(b) 2880(c) 1440(d) 720Correct Answer: (b) 2880Solution:Number 8 letter words such that all consonants are together = 4! 5! = 288028. What is the value of a₁₁ C₁₁ + a₁₂ C₁₂ + a₁₃ C₁₃(a) 0(b) 1(c) Δ(d) - ΔCorrect Answer: (c) ΔSolution:We know that a₁₁ C₁₁ + a₁₂ C₁₂ + a₁₃ C₁₃= Δ29. What is the value of a₂₁ C₁₁ + a₂₂ C₁₂ + a₂₃ C₁₃?(a) 0(b) 1(c) Δ(d) -ΔCorrect Answer: (a) 0Solution:We know that a₂₁ C₁₁+ a₂₂ C₁₂ + a₂₃ C₁₃ = O30. Find the value?(a) 0(b) 1(c) Δ(d) - ΔCorrect Answer: (d) - ΔSolution:Submit Quiz« Previous12345Next »