Solution:Total no of outcomes when two dice are thrown =6x6=36
outcomes when sum is 8= (2, 6) (6, 2) (3, 5) (5,3) (4, 4) = 5
Outcomes when sum is 9
=(3,6) (6, 3) (4, 5) (5,4) =4
Possible number of outcomes =36-(5+4)=36-9=27
∴ Required probability = 27/36 = 34