Solution:
Comparing both sides, we have
ap + br = 0 ...(i)
aq + bs = 0 ...(ii)
cp + dr = 0 ...(iii)
cq + ds = 0 ...(iv)
Solving equation (i) and (iii), we get (ad - bc) p = 0 and (ad - bc) r = 0 Solving equation (ii) amd (iv), we get (ad - bc)q = 0 and (ad - bc)s = 0
Now, If A is non-singular ad - bc ≠ 0.
So, we get, p = q = r = s = 0
So, B is a null matrix.