Solution:Given, (x² - 4x + 3) + (y² - 6x + 8) = 0⇒ (x - 3)(x - 1) + (y - 4)(y - 2) = 0
So, all the possible ends of the diameters of given circle are (3, 4), (3, 2),
(1, 4) and (1, 4).
Also, Radius= √2 and center = (2, 3)
So, the required pair of ends of diameters are
(I) (1, 2) & (3, 4) and
(II) (1, 4) and (3, 2).