Solution:L : x + y + z + 4 = 0 = 2x - y - z - 8 andP : x + 2y + 3z + 1 = 0 is a plane.
Let Dr's of line < a, b, c > Since, line L obtained by intersection of planes
x + y + z +4=0 and 2x - y - z - 8 = 0
So, a + b + c = 0 ..(i)
2a - b - c = 0 ...(ii)
(line is perpendicular to normal of both plane)
a/(- 1 + 1) = b/(2 + 1) = c/(- 1 - 2) = λ (solving (i) and (ii)
a = 0, b = 3λ b = 3λ, c = - 3 λ
Dr's of line is < 0 , 3, - 3 > or < 0 1, - 1 >