Mean, Median & Mode

Total Questions: 53

41. If the mean of the distribution is 24.6, then the value of x is: [SSC MTS 08/10/2021 (Afternoon)]

Correct Answer: (c) 12
Solution:

42. Study the given data and answer the question that follows. [SSC MTS 08/10/2021 (Evening)]


If x is the lower limit of the median class
and y is the upper limit of the modal
class, then the value of (3x + 2y) is:

Correct Answer: (d) 100
Solution:

43. If the mode of the following data is 11, then find the value of k . [SSC MTS 11/10/2021 (Morning)]

11, 8, 9, (2k - 1), 11, 12, 12, 18, 14, 16

Correct Answer: (b) 6
Solution:

44. If the ratio of the mode and median of a certain data is 9 : 8, then the ratio of its mean and median is: [SSC MTS 11/10/2021 (Afternoon)]

Correct Answer: (c) 15 : 16
Solution:

45. The mean of 100 items is 47. It was discovered that three items which should have been 60, 70, 80 were wrongly read as 40, 20, 50, respectively. The correct mean is: [SSC MTS 12/10/2021 (Morning)]

Correct Answer: (a) 48
Solution:

46. The numbers 25, 34, 46, 48, 2x + 1, 4x + 3, 105, 110, 114, 122 are written in ascending order and their median is 77. The value of x is: [SSC MTS 12/10/2021 (Evening)]

Correct Answer: (d) 25
Solution:

47. The median of a set of 11 distinct observations is 17.5. If each of the largest 5 observations of the set is increased by 3, then the median of the new set is: [SSC MTS 13/10/2021 (Morning)]

Correct Answer: (d) remains the same as that of the original set
Solution:

48. If a, b and c are the median, mode and range, respectively, of the data: 8, 5, 4, 3, 2, 7, 3, 10, 9, 17, 12, 3, 8, 4, then what is the value of (3a – 2b + c) [SSC MTS 14/10/2021 (Evening)]

Correct Answer: (d) 27
Solution:

49. If mode of the following data is 14, then what is the value of k ? [SSC MTS 20/10/2021 (Morning)]

11, k, 8, 9, (k – 1), 11, 12, 12, 15, (k – 1), 14

Correct Answer: (c) 15
Solution:

50. If the variance of 5 values is 0.81, then what is its standard deviation? [SSC MTS 26/10/2021 (Morning)]

Correct Answer: (b) 0.9
Solution: