Mensuration (Railway Maths) (Part – VIII)Total Questions: 5041. Four circles of radius r cm are placed such a way that their centres form a square. Find the ratio of the area of the square (formed by the centres of the circles) to the area of the rhombus (formed by the touching points of the circles). [RRB NTPC 14/03/2021 (Evening) ](a) (4 - π) : 1(b) 4 : 1(c) π : 1(d) 2 : 1Correct Answer: (d) 2 : 1Solution:42. A circle of radius 8 cm circumscribed a square. The length of the side of the square is: [RRB NTPC 15/03/2021 (Morning)](a) 2√2 cm(b) 6√2 cm(c) 8√2 cm(d) 4√2 cmCorrect Answer: (c) 8√2 cmSolution:43. Find the area of a triangle whose sides are 5 cm, 7 cm and 11 cm. [RRB NTPC 15/03/2021 (Morning)](a) 12.50 cm²(b) 12.97 cm²(c) 12.30 cm²(d) 12.27 cm²Correct Answer: (b) 12.97 cm²Solution:44. A square park is surrounded by a path of uniform width 1.5 m all around it. The area of the path is 225 m². Find the perimeter of the park. [RRB NTPC 15/03/2021 (Morning)](a) 144.5 m(b) 143 m(c) 144 m(d) 142 mCorrect Answer: (c) 144 mSolution:45. If the perimeter and area of a square are numerically equal then the side of the square is: [RRB NTPC 15/03/2021 (Evening)](a) 4 units(b) 2 units(c) 1 units(d) 16 unitsCorrect Answer: (a) 4 unitsSolution:Perimeter and area are numerically equal, 4a = a² ⇒ a = 4 unit46. Identical square slabs are used to pave the floor of a room 4.5 m long and 1.5 m in broad. Find the minimum number of such slabs that will be needed to pave the floor. [RRB NTPC 19/03/2021 (Morning)](a) 10(b) 3(c) 5(d) 2Correct Answer: (b) 3Solution:47. The hypotenuse of a right isosceles triangle is 28√2 cm. Find the area of the triangle. [RRB NTPC 19/03/2021 (Morning)](a) 396 cm²(b) 784 cm²(c) 392 cm²(d) 468 cm²Correct Answer: (c) 392 cm²Solution:48. The radius of a sphere r is equal to the radius of the base of a right circular cone. The total volume of the two shapes is (7/3)πr³. If 'h' is the height of the cone, find h/r. [RRB NTPC 19/03/2021 (Morning) ](a) 3(b) 2.5(c) 4(d) 2Correct Answer: (a) 3Solution:49. The difference between the circumference and the radius of the circle is 37 cm. The area of the circle is: [RRB NTPC 19/03/2021 (Evening) ](a) 152 cm²(b) 154 cm²(b) 154 cm²(c) 151 cm²Correct Answer: (b) 154 cm²Solution:50. If an equilateral triangle has an altitude of length 12√5 cm, then the difference between the areas of the circumscribed circle and the inscribed circle is: [RRB NTPC 19/03/2021 (Evening)](a) 246π cm²(b) 244π cm²(c) 242π cm²(d) 240π cm²Correct Answer: (d) 240π cm²Solution:Submit Quiz« Previous12345