Solution:Q – S = 2s ⇒ Q = 3sPossible Value of (S, Q) = (4,12) or (5,15)
Again, T = R + S + 3
(i) For, S = 4, Q = 12, T = R + 4 + 3 = R + 7
But equation T = R + 7 is not satisfied for given integer values.
(ii) For S = 5, Q = 15, T = R + 5 + 3 = R + 8
This is satisfied for R = 4 and T = 12
∴ (P, Q, R, S, T) = (10,15,4,5,12)
Now, P + R –T = 10 + 4 – 12 = 2