Missing Number (Varieties Questions)

(1^st number + 2^nd number)² = 3^rd number

In figure (i)

⇒ (7 + 6)² ⇒ (13)² = 169

In figure (ii)

⇒ (9 + 2)² ⇒ (11)² = 121

Similarly,

In figure (iii)

⇒ (9 + 7)² ⇒ (16)² = 256

Hence, "256" is the correct answer.

In figure I :

⇒ (5 × 6)÷ 2 ⇒ 30 ÷ 2 = 15 

In figure II :

⇒ (4 × 9) ÷ 2 ⇒ 36 ÷ 2 = 18

In figure III

⇒ (6 × 7) ÷ 2 ⇒ 42 ÷ 2 = 21

Hence, "21" is the correct answer.

11 → √(13 + 108) = √121

9 → √(26 + 55) = √81

14 → √(7 + 157) ⇒ 196 = ? + 157

⇒ ? = 196 - 157 = 39

13 + 19 = 32 ⇒ (32 ÷ 8) = 4

71 + 9 = 80 ⇒ (80 ÷ 8) = 10

128 + 32 = 160 ⇒ (160 ÷ 8) = 20

3 × 6 = 18

3 × 9 = 27

6 × 9 = 54

In Row

(Digit addition of 1st No. until single unit digit obtained) + 2nd No. = Resultant × 11 = 3rd No.

(23, 5, 110) → 2 + 3 = 5 (single digit)

(5 + 5) × 11 ⇒ 10 × 11 = 110

(56, 9, 121) → 5 + 6 = 11 ⇒ 1 + 1 = 2 (single digit)

(9 + 2) × 11 ⇒ 11 × 11 = 121

(49, 3, 77) → 4 + 9 = 13 ⇒ 1 + 3 = 4 (single digit)

(4 + 3) × 7 ⇒ 7 × 11 = 77

N(N²) are given together in the pattern:

1(1³) = 11,

2(2³) = 28,

3(3³) = 327

5(5³) = 5125

Similarly,

4(4³) = 464

(1st term × 2nd term) + (2nd term × 3rd term) + (1st term × 3rd term) = 4th term

Given set: (3, 5, 7, 71) → (3 × 5) + (5 × 7) + (3 × 7) ⇒ 15 + 35 + 21 = 71 = 4th term

Similarly,

(6, 4, 11, ?) → (6 × 4) + (4 × 11) + (6 × 11) ⇒ 24 + 44 + 66 = 134

In column

$$\times \; (b\; ÷$$

(5 $$\times$$ 6) + {6 $$\times$$ (6 ÷ 2)} ⇒ 30 + 18 = 48

(9 $$\times$$ 2) + {2 $$\times$$ (2 ÷ 2)} ⇒ 18 + 2 = 20

(7 $$\times$$ 8) + {8 $$\times$$ (8 ÷ 2)} ⇒ 56 + 32 = 88

In column

Difference between 1st and 2nd number is double the difference between 2nd and 3rd number.

36 - 28 = 8, 32 - 28 = 4 (8 = 2 $$\times$$ 4)

52 - 40 = 12, 46 - 40 = 6 (12 = 2 $$\times$$ 6)

Similarly,

86 - 12 = 74, 49 - 12 = 37 (74 = 2 $$\times$$ 37)