Correct Answer: (b) f(x) is continuous but not differentiable at x = 1
Solution:f(x)= |x - 1| + x² ∀ x ∈ R
f₁(x)= |x - 1|, f₂(x) = x²
f₁(x) and f(x) both are continuous. Hence f(x) is continuous.
f(x) in differentiable at x = 0
f₁(x) is not differentiable at x = 1.
Hence f(x) is continuous but not differentiable at x = 1.