NUMBER SYSTEM (CDS)Total Questions: 10171. What is the remainder when 4⁹⁶ is divided by 6 ? [2015 (I) Morning Shift ](a) 4(b) 3(c) 2(d) 1Correct Answer: (a) 4Solution:4/6 then remainder = 472. The digit in the unit place of the product 81 × 82 × 83 × 84 ×...× 99 is [2015 (I) Morning Shift ](a) 0(b) 4(c) 6(d) 8Correct Answer: (a) 0Solution:Product of unit digits = 1 × 2 × 3 × 4 × 5 × 6 × 7 × 8 × 9 × 0 × .... = 0 ∴ Required digit in the unit place is 0.73. What is the remainder obtained when 1421 × 1423 × 1425 is divided by 12 ? [2015 (I) Morning Shift ](a) 1(b) 2(c) 3(d) 4Correct Answer: (c) 3Solution:74. Consider the following statements [2015 (I) Morning Shift ]I. The equation 1990x-173 y = 11 has no solution in integers for x and y. II. The equation 3x - 12 y = 7 has no solution in integers for x and y.Which of the above statement(s) is/are correct?(a) Only I(b) Only II(c) Both I and II(d) Neither I nor IICorrect Answer: (c) Both I and IISolution: 75. What is the number of possible pairs of (P, Q), if the number 357P 25Q is divisible by both 3 and 5 ? [2015 (I) Morning Shift ](a) 7(b) 6(c) 5(d) None of theseCorrect Answer: (a) 7Solution:We know that, if the sum of the digits of a number is divisible by 3, then the number is divisible by 3 and if the digit at unit place is 5 or 0, then the number is divisible by 5.76. The difference between the squares of two consecutive odd integers is always divisible by [2015 (I) Morning Shift ](a) 3(b) 7(c) 8(d) 16Correct Answer: (c) 8Solution:Let the two consecutive odd integers be (2x - 1) and (2x + 1) respectively. According to the question, (2x + 1)² - (2x - 1)² = (4x² + 1 + 4x) - (4x² + 1 - 4x) = 4x² + 1 + 4x - 4x² - 1 + 4x = 8x Hence, the difference between the squares of two consecutive odd integers is always divisible by 8.77. What is the maximum value of m, if the number N = 35 × 45 × 55 × 60 × 124 × 75 is divisible by 5ᵐ? [2015 (I) Morning Shift ](a) 4(b) 5(c) 6(d) 7Correct Answer: (c) 6Solution:Here, 35 is divisible by 5 one time. 45 is divisible by 5 one time. 55 is divisible by 5 one time. 60 is divisible by 5 one time. and 75 is divisible by 5 two times. Hence, the maximum value of m is 6.78. A light was seen regularly at an interval of 13 s. It was seen for the first time at 1 h 54 min 50 s (am) and the last time at 3 h 17 min 49 s (am). How many times was the light seen? [2015 (I) Morning Shift ](a) 375(b) 378(c) 383(d) 384Correct Answer: (c) 383Solution:Number of light seen79. Consider the following statements for the sequence of numbers; 11, 111, 1111, 11111,.... . [2015 (I) Morning Shift ]I. Each number can be expressed in the form (4m + 3) where m is a natural number. II. Some numbers are squares.Which of the above statement(s) is/are correct?(a) Only I(b) Only II(c) Both I and II(d) Neither I nor IICorrect Answer: (a) Only ISolution:Given numbers, 11, 111, 1111, 11111, ... ,80. Consider the following statements [2015 (I) Morning Shift ]I. There exists only one prime number p such that (17p + 1) is a square II. If x is the product of 10 consecutive prime numbers starting from 2, then (x+1) is also a prime number.Which of the above statement(s) is/are correct?(a) Only I(b) Only II(c) Both I and II(d) Neither I nor IICorrect Answer: (a) Only ISolution:Submit Quiz« Previous1234567891011Next »